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4 years ago

What number is equivalent to the expanded form shown below

Mathematics

2 answers:

Aliun [14]4 years ago

5 0

Letter B is the correct answer (203.403)

vekshin14 years ago

4 0

BIDMAS= brackets, indices, division, multiplication, addition and subtraction (goes in order)
2*100=200
3*1=3
4*1=4
4/10=0.4
3/1000=0.003

200+3+0.4+0.003= 203.403
The answer is B

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Please help me find 'x' your help would be much appreciated <br><br><br> -Thanks

Vladimir79 [104]

Answer:

x=25.

Step-by-step explanation:

We know because of corresponding angles, the sum of the angle adjacent to (2x-5) and (2x-5) is 180 degrees

2x-5+5x+10=180

7x+5=180

7x=175

x=25

4 0

3 years ago

Brianna has x nickels and y pennies. She has no less than 20 coins worth no more

Bond [772]

Answer:

$y \ge 20 - x$

$y \le 80 -5x$

$(x,y) = (15,5)$

Step-by-step explanation:

Given

$Nickels = x$

$Pennies = y$

$Amount = \$0.80$ maximum

$Coins = 20$ minimum

Required

Solve graphically

First, we need to determine the inequalities of the system.

For number of coins, we have:

$x\ +\ y\ge 20$ because the number of coins is not less than 20

For the worth of coins, we have:

$0.05x\ +\ 0.01y\ \le0.80$ because the worth of coins is not more than 0.80

So, we have the following equations:

$x\ +\ y\ge 20$

$0.05x\ +\ 0.01y\ \le0.80$

Make y the subject in both cases:

$y \ge 20 - x$

$0.01y \le 0.80 - 0.05x$

Divide through by 0.01

$\frac{0.01y}{0.01} \le \frac{0.80}{0.01} -\frac{ 0.05x}{0.01}$

$y \le \frac{0.80}{0.01} -\frac{ 0.05x}{0.01}$

$y \le 80 -5x$

The resulting inequalities are:

$y \ge 20 - x$

$y \le 80 -5x$

The two inequalities are plotted on the graph as shown in the attachment.

$y \ge 20 - x$ --- Blue

$y \ge 80 -5x$ --- Green

Point A on the attachment are possible solutions

At A:

$(x,y) = (15,5)$

4 0

2 years ago

Suppose a shoe factory produces both low-grade and high-grade shoes. The factory produces at least twice as many low-grade as hi

umka2103 [35]

Answer:

The factory should produce 166 pairs of high-grade shoes and 364 pairs of low-grade shoes for maximum profit

Step-by-step explanation:

The given parameters for the shoe production are;

The number of low grade shoes the factory produces ≥ 2 × The number of high-grade shoes produced by the factory

The maximum number of shoes the factory can produce = 500 pairs of shoes

The number of high-grade shoes the dealer calls for daily ≥ 100 pairs

The profit made per pair of high-grade shoed = Birr 2.00

The profit made per of low-grade shoes = Birr 1.00

Let 'H', represent the number of high grade shoes the factory produces and let 'L' represent he number of low-grade shoes the factory produces, we have;

L ≥ 2·H...(1)

L + H ≤ 500...(2)

H ≥ 100...(3)

Total profit, P = 2·H + L

From inequalities (1) and (2), we have;

3·H ≤ 500

H ≤ 500/3 ≈ 166

The maximum number of high-grade shoes that can be produced, H ≤ 166

Therefore, for maximum profit, the factory should produce the maximum number of high-grade shoe pairs, H = 166 pairs

The number of pairs of low grade shoes the factory should produce, L = 500 - 166 = 334 pairs

The maximum profit, P = 2 × 166 + 1 × 364 = 696

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