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Oksana_A [137]
3 years ago
10

Which values complete the function? f(x) = (x-__ )(x+___)

Mathematics
1 answer:
Maurinko [17]3 years ago
4 0

Answer:

(x - 3) (x + 4)

Step-by-step explanation:

roots are  -4  and 3

then

f = (x + 4)(x - 3)

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6+5 x 2 +5+ = <br><br> 67 +84 - 12 x 4 = 16
lozanna [386]

Answer:

6+(5 x 2)+5=21

the way you wrote this was kinda weird so I don't know what you expected as an answer

Step-by-step explanation:

5 x 2=10

10+6=16

16+5=21

21

3 0
3 years ago
HELP!!! Use the factor Theorem to determine whether the binomial x+1 is a factor of the polynomial function f(x) =2x^3-9x^2+13x-
Dovator [93]

ANSWER

A. No because f(c)=-30

EXPLANATION

The given polynomial is

f(x) =2x^3-9x^2+13x-6

If x+1 is a factor , then f(-1) must evaluate to zero.

f( - 1) =2( - 1)^3-9( - 1)^2+13( - 1)-6

f( - 1) =2( - 1)-9( 1)+13( - 1)-6

f( - 1) = - 2-9 - 13-6

f( - 1) = -11 - 19

f( - 1) = - 30

Since f(-1) is not equal to zero, x+1 is not a factor of

f(x) =2x^3-9x^2+13x-6

6 0
3 years ago
ANSWER RIGHT AWAY!!!!​
Burka [1]

Answer:

1st and 3rd are functions, 2nd and 4th are not functions

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Please answer the following
natulia [17]

Answer:

cot∅ = (-2√30)/7.

Step-by-step explanation:

Given the value of csc∅ = -13/7 and ∅ is in quad III.

We know y = r sin∅ and r > 0. So csc∅ = r/y = -13/7 = 13/(-7).

It means y = -7, r = 13.

We know x² + y² = r².

x² = r² - y²

x² = (13)² - (-7)² = 169 - 49 = 120.

x = √120 = 2√30.

we know cot∅ = x/y = (2√30)/(-7) = (-2√30)/7.

Hence, cot∅ = (-2√30)/7.

4 0
3 years ago
PLEASE HELP ASAP WILL MARK BRAINLIEST<br><br>see the pic pls
vovangra [49]

Answer: Your answer is 50

Step-by-step explanation:

3 0
2 years ago
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