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3 years ago

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The vertices of a parallelogram are shown below.

1 answer:

OleMash [197]3 years ago

4 0

The vertices for the dilated image can be found by multiplying the coordinates of the original image by the scale factor. In this problem, the scale factor is 1/3.

(0,0) ⇒ 0 x 1/3 = 0 ; 0 x 1/3 = 0 ⇒ (0,0)
(27,0) ⇒ 27 x 1/3 = 9 ; 0 x 1/3 = 0 ⇒ (9,0)
(36,30) ⇒36 x 1/3 = 12 ; 30 x 1/3 = 10 ⇒ (12,10)
(9,30) ⇒ 9 x 1/3 = 3 ; 30 x 1/3 = 10 ⇒ (3,10)

Answer is choice D. (3,10)

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mart [117]

Answer: $\sum_{n=1}^{5}4^n=1364$

Step-by-step explanation:

Since we have given that

$\sum_{n=1}^{5}4^n$

Now, we know the rule for summation , we'll apply this ,

$\sum_{n=1}^{5}4^n\\=4^1+4^2+4^3+4^4+4^5\\$

Now, it becomes geometric progression, so we us the formula for sum of terms in g.p. which is given by

$S_n=\frac{a(r^n-1)}{r-1}\\\\\text{where 'a' is the first term and 'r' is the common ratio}$

So, our equation becomes ,

$a=4 \\\\r=\frac{a_2}{a_1}=\frac{4^2}{4}=4\\\\S_5=\frac{4(4^5-1)}{4-1}\\\\S_5=1364$

Hence ,

$\sum_{n=1}^{5}4^n=1364$

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3 years ago

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inessss [21]

Answer:

The probability that at most 38 of the 60 relays are from supplier A is P(X≤38)=0.3409.

Step-by-step explanation:

We can model this question with a binomial distribution random variable.

The sample size is n=60.

The probability that the relay come from supplier A is p=2/3 for any relay.

If we use a normal aproximation, we have the mean and standard deviation:

$\mu=np=60*(2/3)=40\\\\\sigma=\sqrt{npq}=\sqrt{60*(2/3)*(1/3)} =3.65$

The probability that at most 38 of the 60 relays are from supplier A is P(X≤38)=0.3409:

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3 years ago

8(y+4)-2(y-1)=70-3y help pls

jeka57 [31]

Answer:

y = 4

Step-by-step explanation:

8(y+4)-2(y-1)=70-3y

8y+32-2y+2=70-3y

Grouping of like terms

8y-2y+3y=70-32-2

9y=36

Divide both sides by 9

9y/9 = 36/9

9 cancels itself and 9.

y=36/9

y=4

Therefore, y = 4.

Hope it helps.

If so, mark as brainliest.

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forsale [732]

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