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3 years ago

10

The vertices of a parallelogram are shown below.

1 answer:

OleMash [197]3 years ago

4 0

The vertices for the dilated image can be found by multiplying the coordinates of the original image by the scale factor. In this problem, the scale factor is 1/3.

(0,0) ⇒ 0 x 1/3 = 0 ; 0 x 1/3 = 0 ⇒ (0,0)
(27,0) ⇒ 27 x 1/3 = 9 ; 0 x 1/3 = 0 ⇒ (9,0)
(36,30) ⇒36 x 1/3 = 12 ; 30 x 1/3 = 10 ⇒ (12,10)
(9,30) ⇒ 9 x 1/3 = 3 ; 30 x 1/3 = 10 ⇒ (3,10)

Answer is choice D. (3,10)

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Answer:

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Step-by-step explanation:

Vertex form of a parabola is given as:

$y = a ( x - h ) ^2 + k$

Where ( $h,k$ ) is the vertex and $(x,y)$ are the points on the parabola.

We are given that, the vertex is (3, -2) and another point on parabola is given as (2, 3).

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First of all, putting the vertex in the vertex equation as given above:

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$y = 5 ( x - 3 ) ^2 -2$

OR

$y+2= 5 ( x - 3 ) ^2$

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