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3 years ago

Write an equation in slope intercept form for the line with slope -4 and why intercept -1

Mathematics

2 answers:

sladkih [1.3K]3 years ago

8 0

Answer:

y = -4x -1

Step-by-step explanation:

The slope intercept form of an equation is

y = mx +b where m is the slope and b is the y intercept

y = -4x -1

Angelina_Jolie [31]3 years ago

8 0

For this case we have that an equation of a line of the slope-intersept form is given by:

$y = mx + b$

Where:

m: It is the slope of the line

b: It is the cut point of the line with the y axis.

They tell us that:

$m = -4\\b = -1$

So the equation is:

$y = -4x-1$

Answer:

y = -4x-1 $y = -4x-1$

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Igoryamba

Step-by-step explanation:

9x^3+6x^2-3x

Cannot be simplified because there are no like terms but can be factored as

=3x(3x−1)(x+1)

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3 years ago

Find f of 1 and f of 4

Dafna1 [17]

You have to check f(1) in each one to see if it's right and for f(4)

4 0

3 years ago

If X²⁰¹³ + 1/X²⁰¹³ = 2, then find the value of X²⁰²² + 1/X²⁰²² = ?

enyata [817]

Step-by-step explanation:

$\bf➤ \underline{Given-} \\$

$\sf{x^{2013} + \frac{1}{x^{2013}} = 2}\\$

$\bf➤ \underline{To\: find-} \\$

$\sf {the\: value \: of \: x^{2022} + \frac{1}{x^{2022}}= ?}\\$

$\bf ➤\underline{Solution-} \\$

Let us assume that:

$\rm: \longmapsto u = {x}^{2013}$

Therefore, the equation becomes:

$\rm: \longmapsto u + \dfrac{1}{u} = 2$

$\rm: \longmapsto \dfrac{ {u}^{2} + 1}{u} = 2$

$\rm: \longmapsto{u}^{2} + 1 = 2u$

$\rm: \longmapsto{u}^{2} - 2u + 1 =0$

$\rm: \longmapsto {(u - 1)}^{2} =0$

$\rm: \longmapsto u = 1$

Now substitute the value of u. We get:

$\rm: \longmapsto {x}^{2013} = 1$

$\rm: \longmapsto x = 1$

Therefore:

$\rm: \longmapsto {x}^{2022} + \dfrac{1}{ {x}^{2022} } = 1 + 1$

$\rm: \longmapsto {x}^{2022} + \dfrac{1}{ {x}^{2022} } = 2$

★ Which is our required answer.

$\textsf{\large{\underline{More To Know}:}}$

(a + b)² = a² + 2ab + b²

(a - b)² = a² - 2ab + b²

a² - b² = (a + b)(a - b)

(a + b)³ = a³ + 3ab(a + b) + b³

(a - b)³ = a³ - 3ab(a - b) - b³

a³ + b³ = (a + b)(a² - ab + b²)

a³ - b³ = (a - b)(a² + ab + b²)

(x + a)(x + b) = x² + (a + b)x + ab

(x + a)(x - b) = x² + (a - b)x - ab

(x - a)(x + b) = x² - (a - b)x - ab

(x - a)(x - b) = x² - (a + b)x + ab

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