Divide each by 100. You get the ratio
765 : 1000
Now divide by 5
153 : 200
You can use this or
0.765 : 1
Answer:
The graph is uploaded in the attachment.
The value of x is 2.625.
Step-by-step explanation:
- let us plot f(x), g(x) on y-axis
so, f(x)=y and g(x)=y.
- the first equation can be written as y=5-2x
- the general equation of a straight is y=mx+c
( where m is the slope and c is the y-intercept )
- now comparing given equation with the general equation mentioned above, the slope of first line is -2 and its y-intercept is 5
- the slope of second equation i.e, y=(2/3)x-2 is 2/3 and its y-intercept is -2.
- now plot the graph using above information.
(y-intercept is the the coordinate of a point where the line intersects y-axis)
(slope is the angle made by the line with the x-axis)
- by seeing the graph, the value of x is 2.625.
Answer:
1,42 * 10 ^ -5
Step-by-step explanation:
La notación científica también se conoce como forma estándar.
Tenemos que realizar la siguiente operación y dejar el resultado en forma estándar.
Entonces;
0,00000826 * 235 × 10 ^ -7 / 0,0017 × 10 ^ -2
También;
8.26 * 10 ^ -6 * 2.35 * 10 ^ -5 / 1.7 * 10 ^ -5
= 19,411 * 10 ^ -11 / 1,7 * 10 ^ -5
= 1,42 * 10 ^ -5
<h3>Answers:</h3>
- (a) It is <u>never</u> one-to-one
- (b) It is <u>never</u> onto
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Explanation:
The graph of any constant function is a horizontal flat line. The output is the same regardless of whatever input you select. Recall that a one-to-one function must pass the horizontal line test. Horizontal lines themselves fail this test. So this is sufficient to show we don't have a one-to-one function here.
Put another way: Let f(x) be a constant function. Let's say its output is 5. So f(x) = 5 no matter what you pick for x. We can then show that f(a) = f(b) = 5 where a,b are different values. This criteria is enough to show that f(x) is not one-to-one. A one-to-one function must have f(a) = f(b) lead directly to a = b. We cannot have a,b as different values.
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The term "onto" in math, specifically when it concerns functions, refers to the idea of the entire range being accessible. If the range is the set of all real numbers, then we consider the function be onto. There's a bit more nuance, but this is the general idea.
With constant functions, we can only reach one output value (in that example above, it was the output 5). We fall very short of the goal of reaching all real numbers in the range. Therefore, this constant function and any constant function can never be onto.
I think that’s the answer
