Answer:
By using hypothesis test at α = 0.01, we cannot conclude that the proportion of high school teachers who were single greater than the proportion of elementary teachers who were single
Step-by-step explanation:
let p1 be the proportion of elementary teachers who were single
let p2 be the proportion of high school teachers who were single
Then, the null and alternative hypotheses are:
: p2=p1
: p2>p1
We need to calculate the test statistic of the sample proportion for elementary teachers who were single.
It can be calculated as follows:
where
- p(s) is the sample proportion of high school teachers who were single (
) - p is the proportion of elementary teachers who were single (
)
- N is the sample size (180)
Using the numbers, we get
≈ 1.88
Using z-table, corresponding P-Value is ≈0.03
Since 0.03>0.01 we fail to reject the null hypothesis. (The result is not significant at α = 0.01)
It would be
2x3xnxn
N has a 1 in front of it it's just not shown
So
2x3x1nx1n then you'd at as much as possible
5x2n
Answer:
infinite soulutions
Step-by-step explanation:
m+7=3+m+4
m+7=m+3+4 (Combine Like Terms)
m+7=m+7
Step 2: Subtract m from both sides
m+7−m=m+7−m
7=7
Answer:111650
Step-by-step explanation:i think its right
Answer:
600$
Step-by-step explanation:
I think this is right