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3 years ago

Determine the general solution: sin 2x=-1/2

1 answer:

8 0

as sin (11pi/6) = -1/2

so

2x= 7pi/6+2npi
and

2x= 11pi/6 + 2npi

solve both of them for x and you will get your answer

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(3-p)^2 How to solve this steps

Zanzabum

Answer:

Look at the attachment

7 0

3 years ago

The product of 4 and a number f decreased by 2 is 15

Debora [2.8K]

Answer: The number is: "2 " .

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Step-by-step explanation:

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Write the expression; which is an equation, as follows:

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" 4x − 12 = 2(-x) " ; in which "x" represents "the number for which we shall solve" .

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Note:

If the "number" = "x" ; the "opposite of the number" = " -x " ;

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Rewrite as: " 4x − 12 = -2x " ;

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→ Add "12" ; & add "2x" ; to EACH SIDE of the equation:

4x − 12 + 12 + 2x = -2x + 12 + 2x ;

to get: 6x = 12 ;

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Now, divide each side of the equation by "6" ;

to isolate "x" on one side of the equation; & to solve for "x" ;

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6x / 6 = 12 / 6 ;

to get: x = 2 .

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Answer: The number is: "2 " .

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Let us check our answer, by plugging in "2" for "x" in our original equation:

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→ " 4x − 12 = 2(-x) " ;

Let us plug in "2" for "x" ; to see if the equation holds true; that is; if both side of the equation are equal; when "x = 2" ;

→ " 4(2) − 12 = ? 2(-2) ??

→ 8 − 12 = ? -4 ? ;

→ -4 = ? -4 ?? Yes!

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7 0

2 years ago

Read 2 more answers

Suppose you have developed a scale that indicates the brightness of sunlight. Each category in the table is 4 times brighter tha

raketka [301]

According to the developed scale, a radiant day is 16 times brighter than a dim day.

We assume the brightness of a dim day to be x.

According to the developed scale, the brightness of an illuminated day will be 4 times that of a dim day.

Thus, the brightness of an illuminated day = 4*the brightness of a dim day = 4x.

According to the developed scale, the brightness of a radiant day will be 4 times that of an illuminated day.

Thus, the brightness of a radiant day = 4*the brightness of an illuminated day = 4*4x = 16x.

Now, the ratio of the brightness of a radiant day to the brightness of a dim day = 16x:x = 16x/x = 16:1.

Thus, according to the developed scale, a radiant day is 16 times brighter than a dim day.

Learn more about the developed scale at

brainly.com/question/4970963

#SPJ1

The question provided is incomplete. The complete question is:

"Suppose you have developed a scale that indicates the brightness of sunlight. Each category in the table is 4 times brighter than the next lower category. For example, a day that is dazzling is 4 times brighter than a day that is radiant. How many times brighter is a radiant day than a dim day?

Dim=2

Illuminated=3

Radiant=4

Dazzling=5"

8 0

1 year ago

Leila runs at 12 miles per hour. Find the number of miles she can travel if she runs for 1 1/2 hours.

mash [69]

Answer:

18 miles

Step-by-step explanation:

Distance = speed * time

d = 12 *1 1/2 = 12*1.5 = 18

5 0

2 years ago

Read 2 more answers

What is the true solution to 3 In 2+In 8 = 2 In(4x)? 60f Š O OOO TNT 00

alina1380 [7]

Answer:

x = 2

Step-by-step explanation:

Taking antilogs, you have ...

2³ × 8 = (4x)²

64 = 16x²

x = √(64/16) = √4

x = 2 . . . . . . . . (the negative square root is not a solution)

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You can also work more directly with the logs, if you like.

3·ln(2) +ln(2³) = 2ln(2²x) . . . . . . . . . . . write 4 and 8 as powers of 2

3·ln(2) +3·ln(2) = 2(2·ln(2) +ln(x)) . . . . use rules of logs to move exponents

6·ln(2) = 4·ln(2) +2·ln(x) . . . . . . . . . . . . simplify

2·ln(2) = 2·ln(x) . . . . . . . . . . . subtract 4ln(2)

ln(2) = ln(x) . . . . . . . . . . . . . . divide by 2

2 = x . . . . . . . . . . . . . . . . . . . take the antilogs

4 0

3 years ago