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murzikaleks [220]
3 years ago
13

Determine the general solution: sin 2x=-1/2

Mathematics
1 answer:
stellarik [79]3 years ago
8 0

as sin (11pi/6) = -1/2

so 

2x= 7pi/6+2npi
and

2x= 11pi/6 + 2npi

solve both of them for x and you will get your answer



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It takes 19 minutes to get from Yermin’s house to the beach. If she has traveled for 5 minutes already, how many more minutes wi
Bezzdna [24]

it will be 14 more minuted because she has completed 5/19 minutes it takes to reach the beach.. we can get this answer by taking the total number of minuted to get to the beach (19) and subtract the number of minutes she has already walked (5)..... our answer is that she has 14 minutes left till she reaches the beach.

8 0
3 years ago
Which table contains only points that lie on the line of the equation y = 6x - 6?​
Fittoniya [83]

Answer:

The answer is G

Step-by-step explanation:

2 x 6 = 12

12 - 6 = 6

_________

-2 x 6 = -12

-12 - 6 = (-18)

7 0
3 years ago
Read 2 more answers
A line passes through the point (2,3) and has a slope of -2. Which is the equation of the line in point-slope form?
almond37 [142]

Answer:

7-2x=y

Step-by-step explanation:

When a point passes through a line it satisfies its equation

(X-x0 )m= y-y0

Slope = m = -2

(X-2 )(-2)=y-3

4-2x=y-3

7-2x=y

7 0
3 years ago
55÷ =5 what is answer​
Andru [333]

Answer:

The answer is 11

Step-by-step explanation:

55÷5= 11

7 0
3 years ago
A fastball is hit straight up over home plate. The ball's height, h (in feet), from the ground is modeled by ℎ = −16푡 ଶ+103푡+5 w
Liono4ka [1.6K]

Question:

A fastball is hit straight up over home plate. The ball's height, h (in feet), from the ground is modeled by h(t)=-16t^2+80t+5, where t is measured in seconds.  Write an equation to determine how long it will take for the ball to reach the ground.

Answer:

t = 5.0625

Step-by-step explanation:

Given

h(t)=-16t^2+80t+5

Required

Find t when the ball hits the ground

This implies that h(t) = 0

So, we have:

0=-16t^2+80t+5

Reorder

-16t^2+80t+5 = 0

Using quadratic formula, we have:

t = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}

Where

a = -16      b =80      c = 5

So, we have:

t = \frac{-80\±\sqrt{80^2 - 4*-16*5}}{2*-16}

t = \frac{-80\±\sqrt{6400 +320}}{-32}

t = \frac{-80\±\sqrt{6720}}{-32}

t = \frac{-80\±82.0}{-32}

This gives:

t = \frac{-80+82.0}{-32} or t = \frac{-80-82.0}{-32}

t = \frac{2}{-32} or t = \frac{-162}{-32}

t = -\frac{2}{32} or t = \frac{162}{32}

But time can not be negative.

So, we have:

t = \frac{162}{32}

t = 5.0625

<em>Hence, time to hit the ground is 5.0625 seconds</em>

3 0
3 years ago
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