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2 years ago

15

2[3x-(4x-6)]=5(x-6)Solve and answer the linear equation.

1 answer:

OleMash [197]2 years ago

8 0

Answer: x = 6

<u>Step-by-step explanation:</u>

2[3x - (4x - 6)] = 5(x - 6)

2[3x - 4x + 6] = 5x - 30

2[-x + 6] = 5x - 30

-2x + 12 = 5x - 30

<u>+2x </u> <u>+2x </u>

12 = 7x - 30

<u>+30 </u> <u> +30 </u>

42 = 7x

$\frac{42}{7} = \frac{7x}{7}$

6 = x

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geniusboy [140]

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kkurt [141]

Answer:

$(x- \frac{2}{5})^{2} = x^2 -\frac{4}{5}x + \frac{4}{25}$

Step-by-step explanation:

You have two methods to expand this binomial.

Method 1

If you have the expression:

$(x- \frac{2}{5})^{2}$

You can write the expression it in the following way:

$(x-\frac{2}{5})^{2}=(x-\frac{2}{5})(x-\frac{2}{5})$

Then, apply the distributive property:

$(x-\frac{2}{5})(x-\frac{2}{5}) = x^2 -\frac{2}{5}x -\frac{2}{5}x+ (\frac{2}{5})\frac{2}{5}$

Simplify the expression:

$(x-\frac{2}{5})^2= x^2 -\frac{4}{5}x+ (\frac{4}{25})$

---------------------------------------------------------------------------------------

Method 2

For any expression of the form:

$(a-b)^2$

Its expanded form will be:

$(a-b)^2= a^2 -2ab + b^2$

If

$a = x$

$b =\frac{2}{5}$

$(x- \frac{2}{5})^{2} = x^2 - 2x\frac{2}{5} + (\frac{2}{5})^2$

$(x- \frac{2}{5})^{2} = x^2 -\frac{4}{5}x + \frac{4}{25}$

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