Answer:
90 minutes or 1.30 hours
Step-by-step explanation:
In 72 minutes, Sue ran 12 miles per hour
In 1 minute, Sue ran 12/72 miles per hour
In 60 minutes, Sue ran (12/72)*60 miles per hour
= 10 miles per hour
Remaining miles after completing 12 miles in 72 minutes = (24-12) = 12 miles.
If the mileage decreases to 2 miles per hour, he will now run = (10 - 2) = 8 miles per hour.
Now,
1 hour = 60 minutes
Sue can run 8 miles in 60 minutes
Sue can run 1 miles in 60/8 minutes
Sue can run 12 miles in (60/8)*12 minutes
= 90 minutes or 1.30 hours
Answer:
P = 0.75
Step-by-step explanation:
Given that P varies directly as I then the equation relating thenm is
P = kI ← k is the constant of variation
To find k use the condition P = 0.5 when I = 4, thus
k =
=
= 0.125
P = 0.125I ← equation of variation
When I = 6, then
P = 0.125 × 6 = 0.75
-5/2+5
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Answer:
Area of part 1: 3 *
= ![15\sqrt{2}](https://tex.z-dn.net/?f=15%5Csqrt%7B2%7D)
Area of part 2: ![3\sqrt{2} * 5\sqrt{2}](https://tex.z-dn.net/?f=3%5Csqrt%7B2%7D%20%2A%205%5Csqrt%7B2%7D)
![=30](https://tex.z-dn.net/?f=%3D30)
Area of entire rectangle: ![30 + 15\sqrt{2}](https://tex.z-dn.net/?f=30%20%2B%2015%5Csqrt%7B2%7D)
Step-by-step explanation:
The area of a rectangle can be found by using formula : length * width.
The area of part 1 can be simplified to this:
3 *
= ![15\sqrt{2}](https://tex.z-dn.net/?f=15%5Csqrt%7B2%7D)
Area of part 2:
![3\sqrt{2} * 5\sqrt{2}](https://tex.z-dn.net/?f=3%5Csqrt%7B2%7D%20%2A%205%5Csqrt%7B2%7D)
![=30](https://tex.z-dn.net/?f=%3D30)
The area of the entire rectangle can simply be added from part 1 and part 2.
For area 2, remember multiplying the square root of 2 twice nullifies the square root. So it becomes 15 * 2, which is equal to 30.
Answer: The height of the ball at time t is given as h = -16t² + 14t + 6 while the height of the receiver hand at time t is given as h = -16t² + 10t + 8
What is an equation?
An equation is an expression that shows the relationship between two or more variables and numbers.
A quarterback throws a football toward a receiver from a height of 6 ft. The initial vertical velocity of the ball is 14 ft/s. At the same time that the ball is thrown, the receiver raises his hands to a height of 8 ft and jumps up with an initial vertical velocity of 10 ft/s.
The height of the ball at time t is given as h = -16t² + 14t + 6 while the height of the receiver hand at time t is given as h = -16t² + 10t + 8