Yea because every input has only one output
Answer:
The length of line segment FG is equal to the length of F'G'
The perimeter of pentagon CDEFG is equal to the perimeter of pentagon C'D'E'F'G.
Step-by-step explanation:
Given
CDEFG and C'D'E'F'G
Translation: 7 units up and 5 units left
Solving (a): Segment FG and F'G'
When a shape is translated, the resulting image will have the same lengths as the original image (i.e, translation does not change measurements)
Hence:
![FG = F'G'](https://tex.z-dn.net/?f=FG%20%3D%20F%27G%27)
Solving (b): Perimeter CDEFG and C'D'EF'G'
In (a), we established that lengths do not change during translation;
Hence:
The perimeter of the CDEFG and C'D'EF'G' will remain the same
Given:
Selling price of a machine = 7000/-
Gross loss = 20%.
To find:
The cost and gross loss.
Solution:
Let x be the cost of machine.
According to the question,
![x-20\%\text{ of }x=7000](https://tex.z-dn.net/?f=x-20%5C%25%5Ctext%7B%20of%20%7Dx%3D7000)
![x-\dfrac{20}{100}x=7000](https://tex.z-dn.net/?f=x-%5Cdfrac%7B20%7D%7B100%7Dx%3D7000)
![x-0.2x=7000](https://tex.z-dn.net/?f=x-0.2x%3D7000)
![0.8x=7000](https://tex.z-dn.net/?f=0.8x%3D7000)
Divide both sides by 0.8.
![x=\dfrac{7000}{0.8}](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B7000%7D%7B0.8%7D)
![x=8750](https://tex.z-dn.net/?f=x%3D8750)
So, the cost of the machine is 8750/-.
Now,
![\text{Gross Loss}=\text{Cost}-\text{Selling price}](https://tex.z-dn.net/?f=%5Ctext%7BGross%20Loss%7D%3D%5Ctext%7BCost%7D-%5Ctext%7BSelling%20price%7D)
![\text{Gross Loss}=8750-7000](https://tex.z-dn.net/?f=%5Ctext%7BGross%20Loss%7D%3D8750-7000)
![\text{Gross Loss}=1750](https://tex.z-dn.net/?f=%5Ctext%7BGross%20Loss%7D%3D1750)
Therefore, the gross loss is 1750/-.
Idk this cause my teacher. Any teach