Question

Consider the chemical reaction:

Answer 1

Answer:

The answer to your question is: 0.118 moles of water

Explanation:

Data

moles of water = ?

Vol of O2= 1.6

Temp = 324°K

Pressure = 0.984 atm

R = 0.082 atm l / mol°K

Process

1.- Calculate the moles of O₂ using the ideal gas formula.

                                PV = nRT

                                $n = \frac{PV}{RT}$

                                $n = \frac{(1.6)(0.984)}{(0.082)(324)}$

                                $n = \frac{1.5744}{26.568}$

                                       n = 0.059 moles of oxygen

2.- Find the moles of water

                                2 moles of water ------------------ 1 mol of oxygen

                                x                           ------------------   0.059 moles

                                x = (0.059 x 2) / 1

                                x = 0.118 moles of water