Answer:
0.1082M of Barium Hydroxide
Explanation:
KHP reacts with Ba(OH)2 as follows:
2KHP + Ba(OH)2 → 2H2O + Ba²⁺ + 2K⁺ + 2P²⁻
<em>Where 2 moles of KHP reacts per mole of barium hydroxide</em>
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To solve this question we must find the moles of KHP in 1.37g. With these moles and the reaction we can find the moles of Ba(OH)2 and its molarity using the volume of the solution (31.0mL = 0.0310L) as follows:
<em>Moles KHP -Molar mass: 204.22g/mol-</em>
1.37g * (1mol / 204.22g) = 0.006708 moles KHP
<em>Moles Ba(OH)2:</em>
0.006708 moles KHP * (1mol Ba(OH)2 / 2mol KHP) =
0.003354 moles Ba(OH)2
<em>Molarity:</em>
0.003354 moles Ba(OH)2 / 0.0310L =
<h3>0.1082M of Barium Hydroxide</h3>
Answer:
Activation energy for the uncatalyzed reverse reaction = 103 kJ/mol
Explanation:
Activation energy decreases from = 56 kj/mol to 35 kj/mol
products = 78 KJ lower in energy than reactants
Activation energy for the uncatalyzed reverse reaction = 103 kJ/mol
attached below are the sketches of approximate energy-level for both catalyzed and uncatalyzed reactions
Answer:
d- 7.58 L
Explanation:
According to Charles's law, the temperature in Kelvin is proportional to the volume of a dry gas when the pressure is constant.
Mathematically, V1/T1 = V2/ T2
V1= initial volume= 6.6 L
T1= Initial temperature= 115 °C= (115 °C +273)=388K
V2= final volume
T2= final temperature= 173 °C= ( 173 °C+ 273)= 446K
Substitute the values,
V2=( V1 × T2)/ T1
= (6.6×446)/388
= 2943.6/388
= 7.6L
3 Ca
2 P
8 O
There 13 mols of atoms.
Answer:
2N₂ + O₂ → 2N₂O
Explanation:
Given equation:
N₂ + O₂ → N₂O
In balancing a chemical equation, the number of atoms on both sides of the expression must be the same.
To solve this problem, we use a simple mathematical approach;
put coefficients a,b and c
aN₂ + bO₂ → cN₂O
Conserving N;
2a = 2c
Conserving O:
2b = c
Let a = 1, c = 1 , b = 
multiply through by 4
a = 2, b = 1 and c = 2
Balanced equation is;
2N₂ + O₂ → 2N₂O