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Fudgin [204]
3 years ago
8

What are the roots of x^3-8=0?

Mathematics
1 answer:
algol [13]3 years ago
7 0

Answer:

hello : x = 2

Step-by-step explanation:

note : a^3 = b^3  : a=b

x^3-8=0

x^3=8

x^3= 2^3

so : x=2

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The normal vector to the plane at (0, 0, 8) is the same as the gradient of the surface at this point, (1, 1, 1). We can get all points along the line containing this vector by scaling the vector by t, then ensure it passes through (0, 0, 8) by translating the line so that it does. Then the line has parametric equation

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3 years ago
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Hey there!

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