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2 years ago

What are the roots of x^3-8=0?

Mathematics

1 answer:

algol [13]2 years ago

7 0

Answer:

hello : x = 2

Step-by-step explanation:

note : a^3 = b^3 : a=b

x^3-8=0

x^3=8

x^3= 2^3

so : x=2

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Please help me no one even bothers to help so plzzzz i BEGGGGGGGGGGG

user100 [1]

Answer:

Here's what I get.

Step-by-step explanation:

When you dilate an object by a scale factor, you multiply its coordinates by the same number.

If the scale factor is 4, the rule is (x, y) ⟶ (4x, 4y)

Your table then becomes

$\begin{array}{lcl}\textbf{Vertices of}& \, & \textbf{Vertices of}\\\textbf{VWXY}& \, & \textbf{V'W'X'Y'}\\V(-1 ,1) & \quad & V'(-4, 4)\\W(-1, 2) & \quad & W'(-4, 8)\\X(2, -1) & \quad & X'(8 ,-4)\\Y(2, 2) & \quad & Y'(8, 8)\\\end{array}$

The diagram below shows figure VVXY as a green bow-tie and its image V'W'X'Y' in orange.

The scale factor is greater than one, so the dilation is an enlargement.

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3 years ago

Use an angle sum identity to derive each double-angle identity.

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A lifeguard received 15 hours of first aid training and 10 hours of cardiopulmonary resuscitation training what is the ratio of

aivan3 [116]

Answer:

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Step-by-step explanation:

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If (4 to the 4 power) to the x power = 4 to the 32 power, what is the value of x?

gizmo_the_mogwai [7]

(4 to the 4 power) to the x power = 4 to the 32 power

(4^4)^x = 4^32

4^4x = 4^32

4x = 32

x = 8

Answer

x = 8

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2 years ago