Answer:
if exterior angle is 10 degrees, then interior angle is 180 -10 = 170 deg.
Each trinaglke inside the polygon will be isosceles with two angles of 170/2 - 85 degrees each.
So, angle at centre = 180 -170 = 10 deg.
Ttal angle at centre = 360 deg.
No of sides = 360 /10 = 36 sided polygon.
b) Sum of interior angles is given by (2N-4) Right angles
So: 9900 = (2N-4)x90 = 180N - 360
180N = 9900 +360 = 10260
N = number of sides = 10260 / 180 = 57 sides
Turn the percent into a decimal which is .20 and then multiply
.20 time 3 is equal to .60
Answer: .60
I'm assuming a quarter-circle is exactly 1/4 of a circle. Thus if you have 4 congruent quarter-circles, that should mean they make a complete circle.
If that is the case, then we can find the area of the full circle using pi*r^2.
So the area of the circle is 5^2*pi or 25pi.
To find the area of the shaded region, we subtract the area of the circle from the area of the square.
The area of the square is 10^2 or 100.
So the area of the shaded region is 100 - 25pi.
My calculator says that equals roughly 21.46
Answer:
A total of 18 gallons of more gas
Step-by-step explanation:
7 gallons = 210 miles
750-210= 540
210*2 =420 miles 7*2=14 gallons
210/2= 105 7/2=3.5 gallons
525 miles 17.5 miles
210/14= 15 7/14=.5 gallons
540 miles 18 gallons
The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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