There are 23 students in a math class 12 of them are boys what is the ratio of girls to total number of students

At a butcher shop, Hilda bought 6 1/4 lb of Beef and some pork. She left with 13 1/20 lb of meat. Express the number of pounds

lina2011 [118]

Hilda bought 15.11 lb of pork.

Step-by-step explanation:

Cost of Beef that Hilda bought = 4 17/20 = 4.85 lb

Cost of the total meat she bought = 19 24/25 = 19.96 lb.

To find the number of pounds of pork she bought, subtract.

Number of pounds of pork she bought = 19.96 - 4.85 = 15.11 lb.

8 0

3 years ago

Read 2 more answers

Many high school students take the AP tests in different subject areas. In 2007, of the 144,796 students who took the biology ex

Nataly [62]

Answer:

$(0.582-0.485) - 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.0942$

$(0.582-0.485) + 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.09978$

And the 90% confidence interval would be given (0.0942;0.09978).

We are confident at 90% that the difference between the two proportions is between $0.0942 \leq p_A -p_B \leq 0.09978$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p_A$ represent the real population proportion female for Biology

$\hat p_A =\frac{84199}{144796}=0.582$ represent the estimated proportion female for biology

$n_A=144796$ is the sample size for A

$p_B$ represent the real population proportion female for calculus AB

$\hat p_B =\frac{102598}{211693}=0.485$ represent the estimated proportion female for Calculus AB

$n_B=211693$ is the sample size required for B

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

For the 90% confidence interval the value of $\alpha=1-0.90=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.64$

And replacing into the confidence interval formula we got:

$(0.582-0.485) - 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.0942$

$(0.582-0.485) + 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.09978$

And the 90% confidence interval would be given (0.0942;0.09978).

We are confident at 90% that the difference between the two proportions is between $0.0942 \leq p_A -p_B \leq 0.09978$

5 0

3 years ago

Q: aling conching baiked 24 dozens of macaroons. She reserved of a dozen for her children. How many dozens were left for her to

AveGali [126]

Answer:

hmmm cant tell if this is a serious question Lol considering you seem pretty smart but if so answer is 23

Step-by-step explanation:

4 0

3 years ago

De que numero es 552 el 8%menos

djyliett [7]

8% of 552 is 44.16. Look at the percent sign as a decimal and move it two places to the left, that'll give you 0.08. To find 8% of 552, look at it as 0.08 multiplied by 552. After you multiply you should get 44.16.

8 0

3 years ago

Simplify the expression. <br> -216) + 3(5 – 4 x 2)

masya89 [10]

Answer:

Step-by-step explanation:

If it's (-216):

(-216) + 3(5 - 4 x 2)

(-216) + 3( -3)

(-216) -9

-225

If it's -2(16):

-2(16) + 3(5 - 4 x 2)

-2(16) + 3(-3)

-32 - 9

-41

4 0

3 years ago