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klio [65]
3 years ago
8

Solve the inequality 45 - 9.9x < - 4.9x

Mathematics
1 answer:
Elena-2011 [213]3 years ago
7 0

Answer:

\large\boxed{x>9\to x\in(9;\ \infty)}

Step-by-step explanation:

45 - 9.9x

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Which of the following best describes the equation y= -2/7x +12
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Nikolay [14]

Replace x with π/2 - x to get the equivalent integral

\displaystyle \int_{-\frac\pi2}^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx

but the integrand is even, so this is really just

\displaystyle 2 \int_0^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx

Substitute x = 1/2 arccot(u/2), which transforms the integral to

\displaystyle 2 \int_{-\infty}^\infty \frac{\cos(u)}{u^2+4} \, du

There are lots of ways to compute this. What I did was to consider the complex contour integral

\displaystyle \int_\gamma \frac{e^{iz}}{z^2+4} \, dz

where γ is a semicircle in the complex plane with its diameter joining (-R, 0) and (R, 0) on the real axis. A bound for the integral over the arc of the circle is estimated to be

\displaystyle \left|\int_{z=Re^{i0}}^{z=Re^{i\pi}} f(z) \, dz\right| \le \frac{\pi R}{|R^2-4|}

which vanishes as R goes to ∞. Then by the residue theorem, we have in the limit

\displaystyle \int_{-\infty}^\infty \frac{\cos(x)}{x^2+4} \, dx = 2\pi i {} \mathrm{Res}\left(\frac{e^{iz}}{z^2+4},z=2i\right) = \frac\pi{2e^2}

and it follows that

\displaystyle \int_0^\pi \cos(\cot(x)-\tan(x)) \, dx = \boxed{\frac\pi{e^2}}

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2 years ago
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8 0
3 years ago
Read 2 more answers
PLEASE HELP FAST!<br><br><br> what is the length of segment AB? <br> 10<br> 12<br> 13<br> 15
ss7ja [257]

Answer:

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Step-by-step explanation:

This triangle appears to be 5 units wide and 12 units tall.

Using the pythagorean theorem, a^2 + b^2 = c^2, we get 25 + 144 = 169 or 13^2.

Therefore the answer is 13.

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3 years ago
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