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Flura [38]
3 years ago
11

Find the area of a triangle with a base length of 6 units and a height of 7 units. (1 point) 10 units 13 units 14 units 21 units

Mathematics
2 answers:
blagie [28]3 years ago
3 0

To solve this problelm you must apply the proccedure shown below:

1. You must apply the formula for calculate the area of a triangle, which is:

Area=\frac{(base)(height)}{2}

2. Now, substitute the values given in the problelm above into the equation:

Area=\frac{(6units)(7units)}{2} \\ Area=21units^{2}

Therefore, as you can see, the answer is: 21units^{2}

Jlenok [28]3 years ago
3 0

Answer: i belive the answer is D, i got it right on the test :) hops this helped

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What is the measure of each interior angle in a regular 30-gon?
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Exterior angles always add up to 360 degrees so for 30-gon each exterior angles is 12 degrees (360/30)

To get the interior angles you subtract 180 from 12 to get 168 degrees
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Alex has collected apples. It has 40 boxes of 8.5 kg each and 6 sacks of 90kg each. Pack the apples in bags of 2.5 kg each. how
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Answer:

40*8.5=340

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3 years ago
Carlos earned $112 for 8 hours of work. AT THIS RATE, how much will he
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4 0
3 years ago
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in a survey, 0.82 of students stated they have homework everyday what is this value written as a fraction
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4 0
3 years ago
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AnyonE wanna help?????
olga_2 [115]

Answer:

Step-by-step explanation:

a). Let the missing term = a

   (a + 7) + (2x - 6) = -4x + 1

   (a + 2x) + (7 - 6) = -4x + 1

   (a + 2x) + 1 = -4x + 1

   (a + 2x) = -4x

   a = -4x - 2x

   a = -6x

   So the equation is,

  (-6x + 7) + (2x - 6) = -4x + 1

b). (a² + p + 1) - (q + 5a + r) = 4a² -2a + 7

   I have assumed p, q and r are the variables at the blank spaces.

   (a² - q) + (p - 5a) + (1 - r) = 4a² - 2a + 7

   By comparing both the sides of the equation,

    a²- q = 4a²

    q = a² - 4a²

    q = -3a²

    p - 5a = -2a

    p = -2a + 5a

    p = 3a

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    r = 1 - 7

    r = -6

    So the equation will be,

    (a² + 3a + 1) - (-3a² + 5a - 6) = 4a²- 2a + 7

3 0
3 years ago
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