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Vedmedyk [2.9K]

3 years ago

12

Can someone answer this for me please and ASAP!

2 answers:

Vladimir79 [104]3 years ago

5 0

I believe it is 8 units.

kiruha [24]3 years ago

4 0

The answer is 8 units

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Can you tell me how they got the answer 35 sq. answer the one with the L looking shape

zloy xaker [14]

Answer: No direct answer needed because it is already given.

Step-by-step explanation: What I usually do with shapes like this is break it up into two shapes. And for this particular shape, it's relatively easy. I spilt the shape into a rectangle and square and went from there. Since the rectangle width is 3, and can subtract that to 5 and get 2, which tells us that the length and width for the square is 4 and 2. Three times nine is twenty-seven. Add that to 8 (which is the result of 4 times 2) and it equals to 35. Hope that helped! :D

6 0

3 years ago

tyler read 15 pages of a book. Ann read 9 pages of the same book. Did Tyler read 4 more pages than Ann? Explain

Slav-nsk [51]

No because fifteen minus nine is six, so Tyler read six more pages than Ann.

5 0

4 years ago

Brut [27]

Answer:

don't type the mathematics questions

7 0

3 years ago

Read 2 more answers

What is the length, in units, of segment CD?

leonid [27]

Answer:

The answet is C.

Step-by-step explanation:

First, you have to find the angle of ACB using Sine Rule, sinθ = opposite/hypotenuse :

$\sin(θ ) = \frac{oppo.}{hypo.}$

$let \: oppo. = 4 \\ let \: hypo. = 5$

$\sin(θ) = \frac{4}{5}$

$θ = {\sin( \frac{4}{5} ) }^{ - 1}$

$θ = 53.1 \: (1d.p)$

Given that line AB is parallel to line CD so ∠C = 90°. Next, you have to find the angle of ACD :

$ACD = 90 - 53.1 = 36.9$

Lastly, you can find the length of CD using Cosine rule, cosθ = adjacent/hypotenuse :

$\cos(θ) = \frac{adj.}{hypo.}$

$let \: θ = 36.9 \\ let \: adj. = 5 \\ let \: hypo. = CD$

$\cos(36.9 ) = \frac{5}{CD}$

$CD \cos(36.9) = 5$

$CD = \frac{5}{ \cos(36.9) }$

$CD = 6.25 units\: (3s.f)$

4 0

3 years ago

25 POINTS: In 1960, 21.5% of U.S. households did not have a telephone. This statistic decreased by 75.8% between 1960 and 1990.

dem82 [27]

Answer: 94.8 % (approx)

Step-by-step explanation:

Let the total household in the U.S is x,

⇒ The total household who did not have a telephone in 1960 = 21.5 % of x

= 0.215 x

According to the question,

The total household who do not have a telephone in 1990 = 75.8 % less than the household in 1960 who did not have the cell phone,

= (100-75.8)% of 0.215x

= 24.2 % of 0.215x

= 0.05203x,

⇒ The household in 1990 who had a telephone = x - 0.05203x = 0.94797x

Hence, the percentage of household who has a telephone in 1990

= $\frac{0.94797x}{x}\times 100$

= $94.797\%\approx 94.8\%$

⇒ Around 94.8% household had telephone in the US in 1990.

7 0

4 years ago