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3 years ago

The decimal number 25.33 is an example of a terminating decimal True/False

Mathematics

1 answer:

Sati [7]3 years ago

3 0

From the research I found 25.33 has an end unlike pi, so is therefore a terminating decimal.

Hope this helps!

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Help!! 50 points and brainliest!

Viktor [21]

Answer:

Second choice:

$x=2t$

$y=4t^2+4t-3$

Fifth choice:

$x=t+1$

$y=t^2+4t$

Step-by-step explanation:

Let's look at choice 1.

$x=t+1$

$y=t^2+2t$

I'm going to subtract 1 on both sides for the first equation giving me $x-1=t$ . I will replace the $t$ in the second equation with this substitution from equation 1.

$y=(x-1)^2+2(x-1)$

Expand using the distributive property and the identity $(u+v)^2=u^2+2uv+v^2$ :

$y=(x^2-2x+1)+(2x-2)$

$y=x^2+(-2x+2x)+(1-2)$

$y=x^2+0+-1$

$y=x^2$

So this not the desired result.

Let's look at choice 2.

$x=2t$

$y=4t^2+4t-3$

Solve the first equation for $t$ by dividing both sides by 2:

$t=\frac{x}{2}$ .

Let's plug this into equation 2:

$y=4(\frac{x}{2})^2+4(\frac{x}{2})-3$

$y=4(\frac{x^2}{4})+2x-3$

$y=x^2+2x-3$

This is the desired result.

Choice 3:

$x=t-3$

$y=t^2+2t$

Solve the first equation for $t$ by adding 3 on both sides:

$x+3=t$ .

Plug into second equation:

$y=(x+3)^2+2(x+3)$

Expanding using the distributive property and the earlier identity mentioned to expand the binomial square:

$y=(x^2+6x+9)+(2x+6)$

$y=(x^2)+(6x+2x)+(9+6)$

$y=x^2+8x+15$

Not the desired result.

Choice 4:

$x=t^2$

$y=2t-3$

I'm going to solve the bottom equation for $t$ since I don't want to deal with square roots.

Add 3 on both sides:

$y+3=2t$

Divide both sides by 2:

$\frac{y+3}{2}=t$

Plug into equation 1:

$x=(\frac{y+3}{2})^2$

This is not the desired result because the $y$ variable will be squared now instead of the $x$ variable.

Choice 5:

$x=t+1$

$y=t^2+4t$

Solve the first equation for $t$ by subtracting 1 on both sides:

$x-1=t$ .

Plug into equation 2:

$y=(x-1)^2+4(x-1)$

Distribute and use the binomial square identity used earlier:

$y=(x^2-2x+1)+(4x-4)$

$y=(x^2)+(-2x+4x)+(1-4)$

$y=x^2+2x+-3$

$y=x^2+2x-3$ .

This is the desired result.

3 0

4 years ago

Read 2 more answers

Can someone explain how to do this? thank you!

Alisiya [41]

The answer will be Negative

Write sin( $\frac{5 \pi }{4}$ ) as sin( $\pi$ + $\frac{ \pi } {4}$ )

Using the summation identity will be:
=sin( $\pi$ )+cos( $\pi$ )sin( $\frac{ \pi }{4}$ )

By following the trivial identity, you should get:
=0* $\frac{ \sqrt{2}}{2}+(-1) \frac{\sqrt 2} {2}$

Remove the parentheses on -1, then multiply
=0* $\frac{ \sqrt 2} {2}-1* \frac{ \sqrt 2} {2}$

You should get:
$- \frac{ \sqrt 2} {2}$

6 0

3 years ago

Not sure how to figure out how to get b2 by itself..can anyone help me out?

Arte-miy333 [17]

As with any "solve for ..." problem, you start by looking at the operations performed on the variable of interest. Here, when you evaluate this expression according to the order of operations, you

add b1
multiply by (h/2)

When you want to solve for b2, you undo these operations in reverse order. To undo multiplication by a fraction, you multiply by the inverse (reciprocal) of the fraction. To undo addition, you add the opposite.

Whatever you do must be done to both sides of the equation.

Here we go ...

... (2/h)A = b1 + b2 . . . . . we undid the multiply by h/2, by multiplying by 2/h

... (2/h)A - b1 = b2 . . . . . we undid the addition of b1 by adding the opposite of b1

Then your solution is

... b2 = 2A/h - b1

If you want to, you can combine these terms over a single denominator to get

... b2 = (2A -h·b1)/h

8 0

4 years ago

If y =2x^2 -4x-5, what is the value of y when x= -3

matrenka [14]

Answer:

Step-by-step explanation:

36+12-5

48-5

4 0

3 years ago

18 is 60% of what number

Ksenya-84 [330]

18 is 60% of 30. I know this because 10% of 30 is 3 and 3 * 6 is 18

3 0

3 years ago