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3 years ago

Solve the equation 4x - 6 = x + 3. Check your solution.

Mathematics

2 answers:

eimsori [14]3 years ago

5 0

,
$4x - 6 = x + 3$

$4x - x = 3 + 6$

3x = 9

Divide by 3

x = 3

motikmotik3 years ago

4 0

4x - 6 = x + 3

Subtract x from each side
4x−6−x=x+3−x
3x−6=3

Add 6 to each side
3x−6+6=3+6
3x=9

Divide each side by 3
3x ÷ 3 = 9 ÷ 3
x = 3
============================================================
Checking work....

Substitute 3 for x in the equation and solve
4(3)- 6 = (3) + 3
12 - 6 = 3 + 3
6 = 6
This is true, so 3 is x

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a) find center of mass of a solid of constant density bounded below by the paraboloid z=x^2+y^2 and above by the plane z=4.(b) F

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Answer: x-bar = y-bar = 0 whereas z-bar = 8/3

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Find the area, by setting the limits as

= $4\cdot \int _0^{\frac{\pi }{2}}\int _0^2\int _{r^2}^4\:rdzdrd\theta$

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3 years ago

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$\bf -7x-2y=4\implies -2y=7x+4\implies y=\cfrac{7x+4}{-2}\implies y=\cfrac{7x}{-2}+\cfrac{4}{-2} \\\\\\ y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{7}{2}} x-2\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill$

$\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-\cfrac{7}{2}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{2}{7}}\qquad \stackrel{negative~reciprocal}{\cfrac{2}{7}}}$

now, what's the slope of a line parallel to that one above? well, parallel lines have exactly the same slope.

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