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Alchen [17]
4 years ago
11

It is known that x=7 is a root of the equation ax^2 + bx + 2= 0, where a<0. Solve the inequality ax²4 +bx^2 + 2>0.

Mathematics
1 answer:
kap26 [50]4 years ago
7 0

Answer:

2/(7a) < x < 7

Step-by-step explanation:

The product of roots of ax² +bx +c is c/a. In this case, that means the second root of the equation is ...

... 2/(7a)

Since a < 0, the parabola opens downward and 2/(7a) < 0. The quadratic function will be positive between the two roots, on the interval ...

... 2/(7a) < x < 7

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Answer:

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Step-by-step explanation:

LCM of  3 a  and  2 b  will be  6 p

Since  a  is odd, which means it's not divisible by 2. Therefore a can be number 1, 3, 5, 7, 9, 11, .......

b  is not divisible by  3, which means b can be number 1, 2, 4, 5, 7, 8, 10, 11, .....

LCM of a and b is P

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