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Alchen [17]
3 years ago
11

It is known that x=7 is a root of the equation ax^2 + bx + 2= 0, where a<0. Solve the inequality ax²4 +bx^2 + 2>0.

Mathematics
1 answer:
kap26 [50]3 years ago
7 0

Answer:

2/(7a) < x < 7

Step-by-step explanation:

The product of roots of ax² +bx +c is c/a. In this case, that means the second root of the equation is ...

... 2/(7a)

Since a < 0, the parabola opens downward and 2/(7a) < 0. The quadratic function will be positive between the two roots, on the interval ...

... 2/(7a) < x < 7

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7 0
3 years ago
I'm new to this and I dont really understand this
agasfer [191]

Answer:

So starting off with 1a f(4)

We simply substitute x with 4 for the function

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Next 1b, here it's a little different since you have to multiply the functions I think ( please correct me if I'm wrong).

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anything to the power of a negative is a fraction so for f^-1(x)=2x-5 we'll have 1/f(x)=x/2+5/2

And then for g^-1, we'll have 1/g(x)=\sqrt{x-3}  \sqrt{x-3}

Hope I helped :)

5 0
2 years ago
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Natalija [7]

Answer:

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Step-by-step explanation:

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