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Anna007 [38]
3 years ago
14

Which factor affects elastic potential energy but not gravitational potential energy?

Physics
2 answers:
Oxana [17]3 years ago
6 0

Answer:

sprig constant

Explanation:

it is correct on edge

Vika [28.1K]3 years ago
3 0

Answer:

The correct answer is the spring constant (k)

Explanation:

  • Elastic potential energy:  Epe = ½ * k * Δx²

k = spring constant

Δx = displacement

  • Gravitational ptential energy: Ep = m*g*h

g = (acceleration due to gravity)

m = mass

h =  relative height of an object to some reference point

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B. The temperature of the water.

The independent variable is the variable that is changed to affect the dependent variable. In this instance, the temperature of the water is being changed to affect the amount of sugar that dissolves.
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3 years ago
. Determine if approximate cylindrical symmetry holds for the following situations. State why or why not. (a) A 300-cm long copp
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Answer:

a) Yes

b) No

Explanation:

In the first case, part a, yes we can say for certainty that cylinderical symmetry holds. Why so? You may ask. This is because from the question, we are told that the length of the rod is 300 cm. And this said length is longer than the distance to the point from the center of the rod, which is 5 cm.

In the second half of the question, I beg to disagree that cylindrical symmetry holds. Again, you may ask why, this is because the length of the rod in this case, is having the same order of magnitude as the distance to the center of the rod. Thus, it is not symmetrical.

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3 years ago
In a $100$ meter track event, Alice runs at a constant speed and crosses the finish line $5$ seconds before Beatrice does. If it
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Answer:

10s

Explanation:

If it took Beatrice 25 seconds to complete the race

Distance = 100 meter

Beatrice speed = 100/25

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If Alice runs at a constant speed and crosses the finish line $5$ seconds, she must have completed the race in 20s (25 -5).

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= 100/20

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3 years ago
Why are there shadows?
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Sam is pulling a box up to the second story of his apartment via a string. The box weighs 53.3 kg and starts from rest on the gr
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Answer:

W = 1222.4 J = 1.22 KJ

Explanation:

The work done on an object is the product of the force applied on it and the displacement it covers as a result of this force. It must be noted that the component of displacement in the direction of force should only be used. Hence, the work can be calculated as:

W = F d Cosθ

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W = Work Done = ?

F = Force Applied = 64 N

d = Distance Covered by Box = 19.1 m

θ = Angle between force and displacement = 0°

Therefore,

W = (64 N)(19.1 m)Cos 0°

<u>W = 1222.4 J = 1.22 KJ</u>

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2 years ago
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