Answer:
1. Light is electromagnetic waves while sound is mechanical.
Light wave is transverse and sound is longitudinal.
Explanation:
2.
<i = <r
3.
when distance between source and obstacle and distance between obstacle and screen is finite then the diffraction is fresnal diffraction
when distance between source and obstacle and distance between obstacle and screen is infinite then the diffraction is Fraunhofer's diffraction
Answer:
The reading in the scale is going to be the same, or if it experiences some change it would be minimum. The reason is because the truck will act as a big closed cage, therefore, when the pigeons fly, the air they move with their wings in order to keep flying, exerts the same force on the closed cage, that if they were standing on the ground.
If the truck however, allows the air flow, the weight might change, because under this scenario, the air flowing could represent less force exerted on the balance.
Explanation:
Answer:
Answer to the question is: 1837.65 millimeters of mercury are equal to 245 kPa.
Explanation:
1 kPa are equal to 7.50062 millimeters of mercury.
1) 5.79 s
2) 98.4 ft/s
Explanation:
1)
The motion of the car is a uniformly accelerated motion (it means it travels with constant acceleration), so we can find the time it takes for the car to stop by using the following suvat equation:
where
s is the distance travelled
v is the final velocity
t is the time
a is the acceleration of the car
In this problem we have:
s = 285 ft is the distance travelled
is the acceleration of the car (negative since the car is slowing down)
v = 0 ft/s is the final velocity of the car, since it comes to a stop
Solving for t, we find:
2)
The initial speed of the car can be found by using another suvat equation, namely:
where
v is the final speed
u is the initial speed
a is the acceleration
t is the time
In this problem, we have:
v = 0 is the final speed of the car
is the acceleration of the car (negative since the car is slowing down)
t = 5.79 s is the total time of motion (found in part 1)
Therefore, the initial speed of the car is:
