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3 years ago

A spring is stretched 5 cm from its equilibrium position. If this stretching requires 30 J of work,

Physics

1 answer:

Triss [41]3 years ago

3 0

Answer:

Best answer will get Brainliest!!!

What is the volume scaled down by a factor of 1/10

Measurements:

Top: 7 in, both sides: 12 in, front: 12 in, back: 12 in, bottom: 7 in

Please help!

Explanation:

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D) circles around the wire that go in at the bottom

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3 years ago

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HELP ME PLSSS What are the possible genotypes

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3 years ago

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. The p.d. at the terminals of a battery is 25V when no load is connected and 24V when a load taking 10A is connected. Determine

makvit [3.9K]

Answer:

the internal resistance of the cell is 0.1 ohm.

Explanation:

Given;

p.d at the terminals of a battery at no load, E₁ = 25 V

p.d at the terminals of a battery at a load, E₂ = 24 V

current through the circuit, I = 10 A

The potential drop across the circuit, V = E₁ - E₂

= 25 V - 24 V

= 1 V

The internal resistance of the cell is calculated as follows;

r = V/I

r = 1 / 10

r = 0.1 ohm

Therefore, the internal resistance of the cell is 0.1 ohm.

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3 years ago

A car traveling at a speed of 13 meters per second accelerates uniformly to a speed of 25 meters per second in 5.0 seconds. 11-

Aleks04 [339]

Answer:

$a=2.4\ m/s^2$

Explanation:

Given that,

Initial speed of a car, u = 13 m/s

Final speed of a car, v = 25 m/s

Time, t = 5 s

We need to find the acceleration of the car during this 5.0 second time interval. Let a is the acceleration. It can be calculated as :

$a=\dfrac{v-u}{t}\\\\a=\dfrac{25-13}{5}\\\\=2.4\ m/s^2$

So, the acceleration of the car is $2.4\ m/s^2$ .

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3 years ago

A large piece of jewelry has a mass of 132.6 g. a graduated cylinder initially contains 48.6 ml water. when the jewelry is subme

Lerok [7]

The density of the substance is 10.5 g/cm³.

The jewelry is made out of Silver.

Density ρ is defined as the ratio of mass m of the substance to its volume V. The cylinder contains a volume V₁ of water and when the jewelry is immersed in it, the total volume of water and the jewelry is found to be V₂.

The volume V of the jewelry is given by,

$V=V_2 -V_1$

Substitute 48.6 ml for V₁ and 61.2 ml for V₂.

$V=V_2 -V_1\\ =61.2 ml -48.6 ml\\ =12.6 ml$

calculate the density ρ of the jewelry using the expression,

$\rho =\frac{m}{V}$

Substitute 132.6 g for m and 12.6 ml for V.

$\rho =\frac{m}{V}\\ =\frac{132.6 g}{12.6 ml} \\ =10.5 g/ml$

Since $1 ml=1 cm^3$ ,

The density of the jewelry is 10.5 g/cm³.

From standard tables, it can be seen that the substance used to make the jewelry is silver, which has a density 10.5 g/cm³.

4 0

3 years ago