<span>Northwest is 45 degrees north of west. If a car travels a distance x miles northwest, its northerly component gains x/sqrt(2) miles and its easterly component LOSES xsqrt(2)/ miles.
Resultant height is h = 4500 + 100x/sqrt(2) - 75x/sqrt(2) = [25/sqrt(2)]x + 4500
dh/dt = [25/sqrt(2)]dx/dt = [25/sqrt(2)]v </span>
Numerator of the equation is 3*nDenominator is 4*p - 5*n The equation is m = 3n/(4p-5n)
Numerator = 3*n
Denominator = 4*p - 5*n
Equation = [m = 3n/(4p-5n)]
Answer:60 miles per hour
Step-by-step explanation:
Hello from MrBillDoesMath!
Answer:
I think your formula (2y/x2) is equivalent to
(2*y)/(x^2) where x^2 means x-squared.
If so, then
(2*y)/(x^2) = (2*3)/(4*4) = 6/16 = 3/8
Thank you,
MrB
X-5y=-21
x=-21+5y
-6(-21+5y)+4y=10
126+-30y+4y=10
126+-26y=10
-26y=-116
y=4.4615
x=1.3076
