Part a: subtract 48-30=18
Part b: i found it by subtracting 48 -30 because it says left over
A=bh
Where b is the base and h is the height
Answer:
a)8
b)13
Step-by-step explanation:
a) ar = c
a^2+b^2=c^2
4^2+7^2=c^2
16+49 = c2
c =
~8
b) sa= c
a2+b2=c2
7^2 + (15-4)^2
49+121 = c2
c=
= 13
I hope im right!!
Answer:
a. f(0) = 4
b. f(6) = 8
Step-by-step explanation:
This is a piecewise function, so the actual equation is on the left, and the inequalities are on the right.
If x = 0, this would fall under the first part of the function because x < 5 is the requirement for the first part. Then, evaluating it: f(0) = 0 + 4 = 4.
If x = 6, this would fall under the second part of the function because 5
x < 7 is the requirement. 6 falls under this category, so that means the second part of the function is used. Because it is a constant, 8, this evaluates to f(6) = 8.