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3 years ago

Suppose that a and b are two independent events with p(a)=0.2 and p(b)=0.4. p(a or b.is

1 answer:

6 0

Recall that

$\mathbb P(A\cup B)=\mathbb P(A)+\mathbb P(B)-\mathbb P(A\cap B)$

Since $A$ and $B$ are independent, we have $\mathbb P(A\cap B)=\mathbb P(A)\cdot\mathbb P(B)$ . So

$\mathbb P(A\cup B)=0.2+0.4-0.2\cdot0.4=0.52$

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A club is selling hats and jackets as a fundraiser. Their budget is $1500, and they want toorder at least 250 items. Each hat co

Tom [10]

Let H be the number hats and J the number of jackets. Then, we can write,

$5H+8J\le1500$

Now, since they want 250 items at least, we can write

$H+J\le250$

Hence, the system of inequalities is

$\begin{gathered} 5H+8J\le1500 \\ H+J\le250 \end{gathered}$

6 0

1 year ago

Suppose there is a pile of quarters dimes and pennies with a total value of $1.07 how much of each coin can be present without b

Korolek [52]

Hello,

Very nice as problem.

2 solutions:
1 quater,8 dimes, 2 pennies
and
3 quaters,3 dimes, 2 pennies

since
107=( 0, 0, 107) but : 100= 0*25+ 0*10+ 100
107=( 0, 1, 97) but : 100= 0*25+ 1*10+ 90
107=( 0, 2, 87) but : 100= 0*25+ 2*10+ 80
107=( 0, 3, 77) but : 100= 0*25+ 3*10+ 70
107=( 0, 4, 67) but : 100= 0*25+ 4*10+ 60
107=( 0, 5, 57) but : 100= 0*25+ 5*10+ 50
107=( 0, 6, 47) but : 100= 0*25+ 6*10+ 40
107=( 0, 7, 37) but : 100= 0*25+ 7*10+ 30
107=( 0, 8, 27) but : 100= 0*25+ 8*10+ 20
107=( 0, 9, 17) but : 100= 0*25+ 9*10+ 10
107=( 0, 10, 7) but : 100= 0*25+ 10*10+ 0
107=( 1, 0, 82) but : 100= 1*25+ 0*10+ 75
107=( 1, 1, 72) but : 100= 1*25+ 1*10+ 65
107=( 1, 2, 62) but : 100= 1*25+ 2*10+ 55
107=( 1, 3, 52) but : 100= 1*25+ 3*10+ 45
107=( 1, 4, 42) but : 100= 1*25+ 4*10+ 35
107=( 1, 5, 32) but : 100= 1*25+ 5*10+ 25
107=( 1, 6, 22) but : 100= 1*25+ 6*10+ 15
107=( 1, 7, 12) but : 100= 1*25+ 7*10+ 5
107=( 1, 8, 2) is good
107=( 2, 0, 57) but : 100= 2*25+ 0*10+ 50
107=( 2, 1, 47) but : 100= 2*25+ 1*10+ 40
107=( 2, 2, 37) but : 100= 2*25+ 2*10+ 30
107=( 2, 3, 27) but : 100= 2*25+ 3*10+ 20
107=( 2, 4, 17) but : 100= 2*25+ 4*10+ 10
107=( 2, 5, 7) but : 100= 2*25+ 5*10+ 0
107=( 3, 0, 32) but : 100= 3*25+ 0*10+ 25
107=( 3, 1, 22) but : 100= 3*25+ 1*10+ 15
107=( 3, 2, 12) but : 100= 3*25+ 2*10+ 5
107=( 3, 3, 2) is good
107=( 4, 0, 7) but : 100= 4*25+ 0*10+ 0

4 0

3 years ago

Write an inequality that represents the following scenario: a number divided by 10 increased by 8 is greater than 15.

Sonbull [250]

$\frac{x}{10}$ + 8 > 15

4 0

3 years ago

Jill buys a t-shirt for $12.79 and a pair of socks for $6.75 at the mall. How much did she spend?

Pie

Answer:

$12.79 + $6.75 = $19.54

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Patricia compró 10 estampillas de correos unas de $3.00 y otras de $1.00. Si pago con $18.00 en total. ¿Cuántas pago por cada un

Ganezh [65]

Answer:

Entonces Patricia necesitara 4 estampas de $3 dolares y 6 estampas de $1 dolar

Step-by-step explanation:

Cuatro estampas de tres dolares cada una es:

3 × 4 = 12

Ahora necesitamos encontrar cuantas estampas mas Patricia puede comprar. Podemos hacer esto restando 12 a 18, que es el costo total de las estampas menos del valor encontrado

18 - 12 = 6

Ahora sabemos que Patricia necesita 6 dolares de estampas ($1 estampas) para acompletar las 10 estampas dando un total de $18 dolares.

6 × 1 = 6 < sumar 6 de 12

12 + 6 = 18

Entonces Patricia necesitara 4 estampas de $3 dolares y 6 estampas de $1 dolar

6 0

3 years ago