All categories

3 years ago

Please help me out on this question

Mathematics

1 answer:

Mariulka [41]3 years ago

7 0

At x=2, y=4

At x=4, y=16

So the total change in y from x=2 to x=4 is 16-4=12

And since average rate of change = total change in y divided by total change in x within the same period, therefore the answer is 12/2 = 6

Hope that helps. Let me know if you have any questions.

You might be interested in

The rock hard company is going to transport truckloads of stones to a highway project. It will cost $4200 to rent trucks, and it

Darya [45]

Answer:

c =4200+275s

Step-by-step explanation:

C is the total cost

4200 is how much to rent the trucks

275 is the price for each ton

s is how many tons of stone in being transported

4 0

4 years ago

Which of the following interpretation for the given sentence is correct?

Nutka1998 [239]

The answer is D because quotient means divide

5 0

3 years ago

Solve for x. x^3=1/27

Tatiana [17]

1/3 is answer. Hope it helps

7 0

3 years ago

What is -4 the square root of 12 + the square root of 75 in simplist radical form?

Fofino [41]

Answer:

The simplest radical form of this mathematical expression is - 3√3

Step-by-step explanation:

1. Let's write in a mathematical expression the information given:

-4 the square root of 12 + the square root of 75

-4 (√12) + √75

-4 (√4 * 3) + (√25 * 3) (12 = 4 * 3 and 75 = 25 * 3)

-4 (2 √3) + 5 √3

-8 √3 + 5√3

- 3 √3

The result is- 3 square root of 3.

The simplest radical form of this mathematical expression is - 3√3

7 0

3 years ago

A random sample of 70 printers discovered that 25 of them were being used in small businesses. find the 95% limit for the popula

kvasek [131]

Answer:

The sample proportion of printers used in small business is:

$\hat{p}=\frac{25}{70}=0.3571$

The 95% confidence interval for the population proportion of printers that are used in small businesses is:

$\hat{p} \pm z_{\frac{0.05}{2}} \sqrt{\frac{\hat{p}(1-\hat{p})}{n} }$

Where:

$z_{\frac{0.05}{2}}=1.96$ is the critical value at 0.05 significance level

$\therefore 0.3571 \pm 1.96 \sqrt{\frac{0.3571(1-0.3571)}{70} }$

$0.3571 \pm 0.1122$

$\left ( 0.3571 - 0.1122, 0.3571 + 0.1122 \right)$

$\left(0.245,0.469 \right)$

Therefore, the 95% confidence interval for the population proportion of printers that are used in small businesses is (0.245 , 0.469)

7 0

3 years ago