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4 years ago

PLEASE HELP WILL GIVE BRAINLIEST Show work please

Mathematics

1 answer:

fenix001 [56]4 years ago

6 0

Answer:

a. $7142.50

Step-by-step explanation:

In my experience computation of health insurance benefits is a mysterious process known only to the insurance company (and not always consistently applied). Here's my take on this set of charges.

10 doctor copays @ $18 each: $180
10 physical therapy visits at (100%-80%)×$150 = $30 each: $300
50 nurse visits at (100%-85%)×$55 each: $412.50
(100%-70%)×$14,500 hospital charge + $300 admission charge: $4650
annual family deductible: $1600

The total of these is ...

$180 +300 +412.50 +4650 +1600 = $7142.50

_____

<em>Comments on this result</em>

It is not clear to me that the Hospital Admission Charge is not a Hospital Charge, but it is apparently not covered by insurance (based on the answers). This computation seems to presume that all charges are non-network. Even though the bills are apparently accumulated by a single individual, the family deductible seems to be charged.

When I use the "single" annual deductible and consider the admission charge part of the hospital charges, I get a total of $5732.50 for out-of-pocket expense. I had to find ways to make the total increase to get it into the range of the offered answers.

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Artyom0805 [142]

Let's begin noting that a triangle is isosceles if and only if two of its angles are congruent. We can thus find the angle <ABP, recalling that the sum of the interior angles of a triangle is equal to 180°.

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3 years ago

How many groups of 3/4 are in each of the following questions?

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Answer:

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Step-by-step exp

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3 years ago

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3 years ago

PLEASE HELP I WILL MARK BRAINLIEST!<br> Question is in the image.

deff fn [24]

Answer:

Step-by-step explanation:

The interquartile range of a data set is the difference between the upper and lower quartiles.

First, put the values in order from least to greatest:

8, 9, 9, 9, 10, 11, 13, 15, 17, 18, 22

To find the upper quartile, we need to first find the median.

The median of this data set is 11, because it is in the middle of the values.

The upper quartile is the median of all the numbers to the left of 11.

The median of 8, 9, 9, 9, and 10 is 9, because it's in the middle.

So the upper quartile is 9.

The lower quartile is the same, but to the right of 11. The median of 13, 15, 17, 18, and 22 is 17 because it's in the middle.

Now, to find the interquartile range, find the difference between 18 and 9.

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3 years ago

**PLEASE HELP WILL GIVE BRAINLIEST** Show work please

PLEASE HELP WILL GIVE BRAINLIEST Show work please