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mart [117]
3 years ago
6

15 minutes is what percentage of One Hour?

Mathematics
1 answer:
Yuki888 [10]3 years ago
4 0

Answer:

25%

Step-by-step explanation:

1 Hr = 60 Minutes

Divide by 15 = 4

100/4 = 25%

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Find the measure of an exterior angle of each regular polygon: 100-gon.
Gelneren [198K]
If this is a 100-gon, then not only does it have 100 sides, it also has 100 central angles.  Each one measures 360/100 = 3.6.  This is the vertex angle for each of those 100 triangles.  180 - 3.6 = 176.4, which has to be split equally between the 2 base angles.  This puts each of those at 88.2.  If you are looking for the exterior angle to each of those, it's the supplement of them. 180-88.2 = 91.8
4 0
3 years ago
-5x + 2 = 67 <br> Can you help me?
coldgirl [10]

Answer:

-13

Step-by-step explanation:

-5x + 2 = 67

-5x = 65

5x = -65

x = -13

8 0
3 years ago
Can I get some help please?
mamaluj [8]

Answer:

1)   68

    / \

 4     17

  /\

2  2

68=2*2*17

2)  104

   /      \

 4      26

  /\       /\

2  2   2   13

104=2*2*2*13

3) 78

    /\

 2    39

        /\

      3   13

78=2*3*13

4) 225

    /\

  9   25

  /\    /\

 3 3  5 5

225=3*3*5*5

Second Part:

1)  45

    /\

  3  15

       /\

      3 5

45=3*3*5

2)  70

     /\

   2   35

          /\

        5  7

70=2*5*7

3)  54

     /\

   9   6

   /\    /\

  3 3  2 3

54=3*3*2*3

4)  126

      /\

    3   42

          /\

         3  14

               /\

              7  2

126=3*3*7*2

3 0
2 years ago
Simplify the expression by combining like terms if possible. If not possible select already simplified. 4a^2+2a+4a^2-5
vichka [17]
So the expression is: 4 a^{2} + 2a + 4 a^{2} - 5

You can combine like terms, which are terms that contain the same variables raised to the same power. That means you can combine the two 4 a^{2}. 4 a^{2} + 4 a^{2} = 8 a^{2} The other terms can't be combined.

Your final answer should be 8 a^{2} +2a-5.
8 0
3 years ago
(8.4x + 2.9) + (-3.7x + 5).
konstantin123 [22]

Answer:

10

Step-by-step explanation:

4 0
4 years ago
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