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ch4aika [34]
3 years ago
8

The sum of two consecutive even integers is 66. Find the numbers.

Mathematics
1 answer:
evablogger [386]3 years ago
4 0
Let the consecutive even numbers be n and n+2.
From given condition, 
n + n+2 = 66
2n = 64
∴ n = 32.
Therefore, the two consecutive even numbers are.
n = 32 and n+2 = 34.
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(PLEASE ANSWER QUICK) Which data set could be represented by the box plot shown below?
Naily [24]

Answer:

Your answer is B

Step-by-step explanation:

The lowest number is 4, therefore it cannot be C.

Now you'll have to cross out numbers on both sides and your mean will be 9 because you'll have to add 8 and 10 together and 18 divided by 2 is 9.

Next, put a line between 8 and 10, now the 8 side is the lower quartile and the 10 side is the greater quartile.

For the lower quartile, add 7 and 7 together, divide 14 by 2 and the lower quartile is 7.

For the greater quartile, add 11 and 13 together, that's 24, divide 24 by 2 and that's 12.

Lowest: 4

Mean: 9

Lower quartile: 7

Greater quartile: 12

Highest: 14

Therefore your answer is B and not A or C.

8 0
3 years ago
A vet bill for your dog is $145. The bill includes $23 per vaccination shot and a $53 office fee. How many shots did your pet re
deff fn [24]
Subtract $145-$53 and you will get 92.
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4 0
3 years ago
Read 2 more answers
After a long study, tree scientists conclude that a eucalyptus tree will grow at the rate of 0.5 6/ (t+4)3 feet per year, where
kipiarov [429]

Answer:

<h2>a) 0.5367feet</h2><h2>b) 0.5223feet</h2><h2>c) 0.7292feet</h2>

Step-by-step explanation:

Given the rate at which an eucalyptus tree will grow modelled by the equation 0.5+6/(t+4)³ feet per year, where t is the time (in years).

The amount of growth can be gotten by integrating the given rate equation as shown;

\int\limits {0.5 + \frac{6}{(t+4)^{3} }  } \, dt \\= \int\limits {0.5} \, dt + \int\limits\frac{6}{(t+4)^{3} }  } \, dx } \, \\= 0.5t +\int\limits {6u^{-3} } \, du \  where \ u = t+4 \ and\ du = dt\\= 0.5t + 6*\frac{u^{-2} }{-2} + C\\= 0.5t-3u^{-2} +C\\= 0.5t-3(t+4)^{-2} + C

a)  The number of feet that the tree will grow in the second year can be gotten by taking the limit of the integral from  t =1 to t = 2

\int\limits^2_1 {0.5 + \frac{6}{(t+4)^{3} }  } \, dt = [0.5t-3(t+4)^{-2}]^2_1\\= [0.5(2)-3(2+4)^{-2}] - [0.5(1)-3(1+4)^{-2}]\\= [1-3(6)^{-2}] - [0.5-3(5)^{-2}]\\ = [1-\frac{1}{12}] - [0.5-\frac{3}{25} ]\\= \frac{11}{12}-\frac{1}{2}+\frac{3}{25}\\   = 0.9167 - 0.5 + 0.12\\= 0.5367feet

b)  The number of feet that the tree will grow in the third year can be gotten by taking the limit of the integral from  t =2 to t = 3

\int\limits^3_2 {0.5 + \frac{6}{(t+4)^{3} }  } \, dt = [0.5t-3(t+4)^{-2}]^3_2\\= [0.5(3)-3(3+4)^{-2}] - [0.5(2)-3(2+4)^{-2}]\\= [1.5-3(7)^{-2}] - [1-3(6)^{-2}]\\ = [1.5-\frac{3}{49}] - [1-\frac{1}{12} ]\\  = 1.439 - 0.9167\\= 0.5223feet

c) The total number of feet grown during the second year can be gotten by substituting the value of limit from t = 0 to t = 2 into the equation as shown

\int\limits^2_0 {0.5 + \frac{6}{(t+4)^{3} }  } \, dt = [0.5t-3(t+4)^{-2}]^2_0\\= [0.5(2)-3(2+4)^{-2}] - [0.5(0)-3(0+4)^{-2}]\\= [1-3(6)^{-2}] - [0-3(4)^{-2}]\\ = [1-\frac{1}{12}] - [-\frac{3}{16} ]\\= \frac{11}{12}+\frac{3}{16}\\   = 0.9167 - 0.1875\\= 0.7292feet

8 0
3 years ago
which statement is true of the function f(x) = -³√x ? check all that apply. a). the function is always increasing. b). the funct
attashe74 [19]

<u>Answers</u>

The function has a domain of all real numbers . True

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The function is always increasing. False

<em>When getting the cube root of a number the result is alway smaller. So the domain of the function should be decreasing not increasing.</em>

The function has a range of {y|– < y < } . False

The function passes through the point (3, –27) . False

<em>When this values are substituted it the function they don't satisfy it. </em>

7 0
3 years ago
Read 2 more answers
2 1/3 divided by 1 2/3 equals
fgiga [73]
2 1/3 ÷ 1 2/3

change to improper fraction.

= 7/3 ÷ 5/3

7/5

= 1 2/5
3 0
3 years ago
Read 2 more answers
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