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maw [93]
3 years ago
14

Read the description of Mike’s work, and identify his profession. Mike’s job is to record sounds in a studio. He studies a video

and physically recreates ambient sounds such as the opening and closing of a drawer, the creaking of a chair when a person sits down, and the sound of a keyboard when a person types on it. Mike is a
.
Computers and Technology
2 answers:
adoni [48]3 years ago
8 0

Answer:

The correct answer would be, Audio Engineer.

Explanation:

An Audio Engineer is also called as Sound Engineer or Recording Engineer. The work of an Audio Engineer is to produce ambient sounds. The Audio Engineer recreates sounds of things that cannot be produced by mouth of a person, like for example they may create sound of trees in the stormy night, the sound of wind, the sound of windows, the creaking of chair when a person sits on it, sound of keyboard when a person types on it, opening and closing of doors, etc. All such type of sounds are made by audio engineers. They use a mix of audio effects to produce the most accurate sounds of the type. So Mike is An Audio Engineer.

kipiarov [429]3 years ago
7 0
Mike is a Sound Engineer
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Answer:

a.) k² - 3k + 3

b.) 1/(1 - k)²

c.) k^{2}  - 3k + 3 * \frac{1}{(1 - k)^{2} }\\\\= \frac{k^{2} - 3k + 3 }{(1-k)^{2} }

Explanation:

a.) A packet can make 1,2 or 3 hops

probability of 1 hop = k  ...(1)

probability of 2 hops = k(1-k)  ...(2)

probability of 3 hops = (1-k)²...(3)

Average number of probabilities = (1 x prob. of 1 hop) + (2 x prob. of 2 hops) + (3 x prob. of 3 hops)

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                                                       = k + 2k - 2k² + 3(1 + k² - 2k)

∴mean number of hops                = k² - 3k + 3

b.) from (a) above, the mean number of hops when transmitting a packet is k² - 3k + 3

if k = 0 then number of hops is 3

if k = 1 then number of hops is (1 - 3 + 3) = 1

multiple transmissions can be needed if K is between 0 and 1

The probability of successful transmissions through the entire path is (1 - k)²

for one transmission, the probility of success is (1 - k)²

for two transmissions, the probility of success is 2(1 - k)²(1 - (1-k)²)

for three transmissions, the probility of success is 3(1 - k)²(1 - (1-k)²)² and so on

∴ for transmitting a single packet, it makes:

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T = ∑ n(1 - k)²(1 - (1 - k)²)

    n-1

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c.) Mean number of required packet = ( mean number of hops when transmitting a packet × mean number of transmissions by a packet)

from (a) above, mean number of hops when transmitting a packet =  k² - 3k + 3

from (b) above, mean number of transmissions by a packet = 1/(1 - k)²

substituting: mean number of required packet =  k^{2}  - 3k + 3 * \frac{1}{(1 - k)^{2} }\\\\= \frac{k^{2} - 3k + 3 }{(1-k)^{2} }

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