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8_murik_8 [283]
3 years ago
12

If DE=4x+10, EF =2x-1, and DF=9x-15, find DF

Mathematics
2 answers:
Ket [755]3 years ago
8 0

Answer:

DF=201

Step-by-step explanation:

We have been given that segment DE=4x+10, segment EF=2x-1 and DF=9x-15

From the given information, we can set an equation as:

DF=DE+EF

9x-15=4x+10+2x-1

Combine like terms:

9x-15=6x+9

9x-15+15=6x+9+15

9x=6x+24

9x-6x=6x-6x+24

3x=24

\frac{3x}{3}=\frac{24}{3}

x=24

DF=9x-15

DF=9(24)-15

DF=216-15

DF=201

Therefore, DF equals 201 units.

svetoff [14.1K]3 years ago
7 0

Answer:


Step-by-step explanation:

If DE = 4x+10,EF =2X -1, and DF= 9x - 15 find DF

(de + ef ) - df = 2e || 2e/2 = e || ed - e = d || ef - e = f || f + d =  df

de + ef = 6x + 11 || (6x +11) - df = -3x -6 || 2e/2 = -3x/2 - 3  || (-3x/2 - 3) - de = x/2 + 7||  (- 3x/2 - 3) - ef = -x/2 - 1|| d + f = 6


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