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laila [671]
3 years ago
8

Which of the following statements are true? Select all that apply

Mathematics
1 answer:
trapecia [35]3 years ago
8 0

Answer:

<h3>1) The correlation coefficient gives us information as to how strong the linear association is between two quantitative variables.</h3><h3>2) The Correlation coefficient has units of measurement and does always lie between -1.0 and +1.0</h3><h3>3) The closer the absolute value of r is to 1, the stronger the relationship is between the two variables. </h3>

Step-by-step explanation:

The choices are

1) The correlation coefficient gives us information as to how strong the linear association is between two quantitative variables.

2) The Correlation coefficient has units of measurement and does always lie between -1.0 and +1.0

3) The closer the absolute value of r is to 1, the stronger the relationship is between the two variables.

4) A correlation coefficient of r=0 indicates a strong linear relationship between two variables.

The correlation coefficient is a number from -1 to 1, which indicates how strong can be the correlation between variables. It could be a strong positive correlation or a strong negative correlation. If the correlation coefficient is close to -1, then it's a strong negative correlation. If the correlation coefficient is close to 1, then it's a strong positive correlation.

Therefore, the first choice is correct.

The second choice is also correct, because the correlation coefficient is restricted to the interval [-1, 1].

The third choice is also crrect, because 1 represents a strong correlation between variables, but to have full answer, it should say "a strong positive corrrelation".

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Answer:

f(0,0)=ln19

Step-by-step explanation:

f(x,y)=ln(\frac{19x^2-x^2y^2+19y^2}{x^2+y^2}) is given as continuous function, so there exist lim_{(x,y)\rightarrow(0,0)}f(x,y) and it is equal to f(0,0).

Put x=rcosA annd y=rsinA

f(r,A)=ln(\frac{19r^2cos^2A-r^2cos^2A*r^2sin^2A+19r^2sin^2A}{r^cos^2A+r^2sin^2A})=ln(\frac{19r^2(cos^2A+sin^2A)-r^4cos^2Asin^a}{r^2(cos^2A+sin^2A)})

we know that cos^2A+sin^2A=1, so we have that

f(r,A))=ln(\frac{19r^2-r^4cos^2Asin^a}{r^2})=ln(19-r^2cos^2Asin^2A)

lim_{(x,y)\rightarrow(0,0)}f(x,y)=lim_{r\rightarrow0}f(r,A)=ln19

So f(0,0)=ln19.

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Step-by-step explanation:

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Michele is purchasing new clothes for soccer practice for the upcoming season. She buys s pairs of shorts at $14.98 each. She al
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Answer:

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Step-by-step explanation:

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Therefore, by adding the shorts and shirt together, we get the expression:

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Step-by-step explanation:

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