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NARA [144]
3 years ago
15

What is DC if AC = 10 cm, BC = 6 cm, and EC = 12 cm? using the options below

Mathematics
2 answers:
NNADVOKAT [17]3 years ago
8 0
The answer is A. Or 5 cm.

Hope this helps,

kwrob
Komok [63]3 years ago
4 0

To solve this question we will use a theorem called the intersecting secant theorem which states that "if 2 secants of a circle intersect outside the circle then product of their segments are equal".

Thus, applying this theorem in this question we see that:AC\times BC=EC\times DC

Thus, 10\times 6=12\times DC

Thus, DC\frac{10\times 6}{12}=5 cm

Thus, out of the given options, the first option is the correct option.


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Find the Jacobian ∂(x, y, z) ∂(u, v, w) for the indicated change of variables. If x = f(u, v, w), y = g(u, v, w), and z = h(u, v
jeyben [28]

Answer:

The Jacobian ∂(x, y, z) ∂(u, v, w) for the indicated change of variables

= -3072uv

Step-by-step explanation:

<u>Step :-(i)</u>

Given  x = 1 6 (u + v)  …(i)

  Differentiating equation (i) partially with respective to 'u'

               \frac{∂x}{∂u} = 16(1)+16(0)=16

  Differentiating equation (i) partially with respective to 'v'

              \frac{∂x}{∂v} = 16(0)+16(1)=16

  Differentiating equation (i)  partially with respective to 'w'

               \frac{∂x}{∂w} = 0

Given  y = 1 6 (u − v) …(ii)

  Differentiating equation (ii) partially with respective to 'u'

               \frac{∂y}{∂u} = 16(1) - 16(0)=16

 Differentiating equation (ii) partially with respective to 'v'

               \frac{∂y}{∂v} = 16(0) - 16(1)= - 16

Differentiating equation (ii)  partially with respective to 'w'

               \frac{∂y}{∂w} = 0

Given   z = 6uvw   ..(iii)

Differentiating equation (iii) partially with respective to 'u'

               \frac{∂z}{∂u} = 6vw

Differentiating equation (iii) partially with respective to 'v'

               \frac{∂z}{∂v} =6 u (1)w=6uw

Differentiating equation (iii) partially with respective to 'w'

               \frac{∂z}{∂w} =6 uv(1)=6uv

<u>Step :-(ii)</u>

The Jacobian ∂(x, y, z)/ ∂(u, v, w) =

                                                         \left|\begin{array}{ccc}16&16&0\\16&-16&0\\6vw&6uw&6uv\end{array}\right|

   Determinant       16(-16×6uv-0)-16(16×6uv)+0(0) = - 1536uv-1536uv

                                                                                 = -3072uv

<u>Final answer</u>:-

The Jacobian ∂(x, y, z)/ ∂(u, v, w) = -3072uv

 

               

     

6 0
3 years ago
Line segmentAB has vertices A(−3, 4) and B(1, −2) . A dilation, centered at the origin, is applied to AB⎯⎯⎯⎯⎯ . The image has ve
zysi [14]

Answer:

The scale factor is

\frac{1}{3}

Step-by-step explanation:

Line segmentAB has vertices A(−3, 4) and B(1, −2) .

A dilation, centered at the origin, is applied to AB. The image has vertices

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We know the rule for dilation by scale factor of k, is

(x,y)\to(kx,ky)

This means that;

A(-3,4)\to A'(-3k,4k)

But we know, A' has coordinates (-1,4/3)

This means that

- 3k =  - 1

k =  \frac{1}{3}

We could also compare:

4k=4/3

Which gives

k=⅓

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If your bill at a restaurant is $44.33, tax is 6.5% and you want to leave a 15% tip how much $ is your total bill? Round your an
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Step-by-step explanation:

x+3/x-2 - 1-x/x= 17/4

now let's put the expression on the upper side so it I'll be

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IRINA_888 [86]

Answer:0.0081  or 0.81%

Step-by-step explanation:

The required probability is P(3,5,0.1)= C5 3 * p^3*q^2, where

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p is the probability that one randomly selected calculator is defective= 10%=0.1

q is the probability that one randomly selected calculator is non-defective.

q=1-p=1-0.1=0.9

So P(3,5,0.1)= 10*0.1^3*0.9^2=0.01*0.81=0.0081

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