According to the identity if a+b+c=0
then a3+b3+c3=3abc
a3+b3+c3/abc=3
a2*a/bc*a+b2*b/ca*b+c2*c/ab*c=3
cancel a,b,c in all the fraction then you get
<span>a²/bc+b²/ca+c²/ab=3.
</span>hence proved
Consider the right triangle ABC with legs AB=4, AC=3 and hypotenuse BC=5. Angle B has
and
.
Since O lies in second quadrant
and
.
Answer: 
.
Step-by-step explanation:
440÷100×12
52.8
440-52.8
387.2
MARK ME BRAINLIEST PLSSSSSS
Answer:
saannn Wala Naman
Step-by-step explanation:
HAHAHAJAH BLABLA
THANKS SA POINTS
Answer:
its 11 and 31
Step-by-step explanation:
got it right on test
