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NISA [10]
3 years ago
6

Find the Inverse for the linear function. J(x)= 5x - 6 F1(x)=

Mathematics
1 answer:
kondaur [170]3 years ago
4 0
F-1(x) = x\5 + 6/5
hope this helps
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Write the ordered pairs relation
EastWind [94]

Answer:

There are no ordered pairs to relate too so i will tell the relation between a pair of numbers and a ordered pair.

Step-by-step explanation:

For an ordered pairs, each point is defined by 2 values.

7 0
3 years ago
Solve for x. x÷(-2)=1.4​
nignag [31]

Answer:

x=-2.8

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Solve for b.<br> 7<br> b<br> 12<br> b= ✓ [?]<br> Pythagorean Theorem: a2 + b2 = c2<br> Enter
fomenos

Answer: b=\sqrt{95}

Step-by-step explanation:

To solve for b, we want to use the Pythagorean Theorem as given.

b and 7 are the legs, and 12 is the hypotenuse.

7^2+b^2=12^2      [exponent]

49+b^2=144     [subtract both sides by 49]

b^2=95               [square root both sides]

b=\sqrt{95}

Now we know b=\sqrt{95}.

6 0
2 years ago
You have 800 square feet of the room reserved for tables
Sav [38]
I hope this helps for question a=16
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8 0
3 years ago
Find the slope of the line that passes through (6, 7) and (2, 10). and simplify if needed thx guys.
tekilochka [14]

Answer:

-\frac{3}{4}

Step-by-step explanation:

the equation for finding the slope of a line when given two points is \frac{y_2-y_1}{x_2-x_1}, aka the change in y over the change in x.

pick one of your coordinate pairs to be y_2\\ and x_2. it doesn't matter which coordinate pair you choose as long as you keep them as y_2\\ and x_2. the remaining coordinate pair will be y_1 and x_1.

for this example, i'll use (2, 10) for y_2\\ and x_2 and (6, 7) for y_1 and x_1.

<em>**before i begin, i just want to note that you can do these next four steps in any order that you want. i personally prefer to plug in my y-values first and then my x-values, but you can choose to instead plug in the values of each coordinate pair (like starting by plugging in the coordinate pair (2, 10) with 10 for </em>y_2\\ and 2 for x_2<em>). it's up to you. i'm going to explain the steps by plugging in my y-values first and then my x-values because that's the way i normally do it.</em>

<em />

first, start by plugging in the y-value from the coordinate pair of your choosing in for y_2\\. since i chose (2, 10) for y_2\\ and x_2, i'll plug in 10 for y_2\\.

\frac{y_2-y_1}{x_2-x_1} ⇒ \frac{10-y_1}{x_2-x_1}

then plug in the remaining coordinate pair's y-value in for y_1. since the coordinate pair that's left is (6, 7), i will plug in 7 for y_1.

\frac{y_2-y_1}{x_2-x_1} ⇒ \frac{10-7}{x_2-x_1}

now i'm going to plug in the x-values. i chose (2, 10) to plug in for y_2\\ and x_2, so now i'll plug in 2 for x_2.

\frac{y_2-y_1}{x_2-x_1} ⇒ \frac{10-7}{2-x_1}

and all that's left to plug in is the x-value from (6, 7), so i will plug that in for x_1.

\frac{y_2-y_1}{x_2-x_1} ⇒ \frac{10-7}{2-6}

after plugging in all the values, you have \frac{10-7}{2-6}.

subtract 10 - 7 as well as 2 - 6.

\frac{10-7}{2-6} ⇒ \frac{3}{-4}

\frac{3}{-4} cannot be simplified, therefore the slope of the line is \frac{3}{-4} or -\frac{3}{4}.

i hope this helps! have a lovely day <3

7 0
2 years ago
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