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3 years ago

Evaluate the expression. 42+5⋅32−42÷23 CLEAR CHECK 12.625 222 45 59

Mathematics

1 answer:

lidiya [134]3 years ago

5 0

Answer:

$\frac{4604}{23}$ or 200.173913

Step-by-step explanation:

$42+(5)(32)-\frac{42}{23} \\\\=42+160-\\\frac{42}{23}\\\=202-\frac{42}{23} =\frac{4604}{23}$

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valentina_108 [34]

Answer:

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Step-by-step explanation:

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What is the ratio of 2 cups of flour and 1 cup of milk.

Marina86 [1]

Answer:

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3 years ago

Nancy shot a 16 on 4 holes of golf. At this rate, what can she expect her score to be if she plays 18 hole? Round to the nearest

Nataliya [291]

Answer:

108.

Step-by-step explanation:

"At this rate, ..." means we're to assume Nancy's score is proportional to the number of holes:

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Find the integration of (1-cos2x)/(1+cos2x)

slega [8]

Given:

The expression is:

$\dfrac{1-\cos 2x}{1+\cos 2x}$

To find:

The integration of the given expression.

Solution:

We need to find the integration of $\dfrac{1-\cos 2x}{1+\cos 2x}$ .

Let us consider,

$I=\int \dfrac{1-\cos 2x}{1+\cos 2x}dx$

$I=\int \dfrac{2\sin^2x}{2\cos^2x}dx$ $[\because 1+\cos 2x=2\cos^2x,1-\cos 2x=2\sin^2x]$

$I=\int \dfrac{\sin^2x}{\cos^2x}dx$

$I=\int \tan^2xdx$ $\left[\because \tan \theta =\dfrac{\sin \theta}{\cos \theta}\right]$

It can be written as:

$I=\int (\sec^2x-1)dx$ $[\because 1+\tan^2 \theta =\sec^2 \theta]$

$I=\int \sec^2xdx-\int 1dx$

$I=\tan x-x+C$

Therefore, the integration of $\dfrac{1-\cos 2x}{1+\cos 2x}$ is $I=\tan x-x+C$ .

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3 years ago

Keisha is solving the equation 7^x=9.

olganol [36]

$\bf \textit{Logarithm of exponentials}\\\\
log_a\left( x^ b \right)\implies b\cdot log_a(x)\\\\
-------------------------------\\\\
7^x=9\implies \boxed{log(7^x)=log(9)}\implies x\cdot log(7)=log(9)
\\\\\\
x=\cfrac{log(9)}{log(7)}$

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3 years ago