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Vlada [557]
3 years ago
8

Diagram of x+3 and of 2x when x is 2

Mathematics
1 answer:
Naya [18.7K]3 years ago
7 0

Answer:

5 and 4

Step-by-step explanation:

So if, x equals 2 then all you do is turn the x into a 2.

So you rewrite the equation into,

2 + 3 and 2 x 2,

Which would be 5 and 4

Hope this helps!

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kumpel [21]

Answer:

Dwow haha salamat sa poiñts idolo stay safe hakd9g

5 0
2 years ago
What expression is not equivalent to 1/343
GREYUIT [131]
1 / 343
This is just equal to 
1 / 7^3 = 7^-3

A. 7^-1 * 7^-2 = 7^(-1 + -2) = 7^-3
B. 7^7 * 7^-10 = 7^( 7+ -10) = 7^-3
C. 7^-2 * 7^-5 = 7^(-2 + -5) = 7^-7
D. 7^-5 * 7^2 = 7^(-5 + 2) = 7^-3

So the correct answer is letter C. 7^-2 * 7^-5
7 0
3 years ago
Trimble Graphic Design receives $2,250 from a client billed in a previous month for services provided. Which of the following ge
krok68 [10]

Answer:

Dr   Cash/Bank $2,250

Cr   Account Receivable $2,250

Step-by-step explanation:

At the time the transaction was carried out, that is the previous month, the accounting entries was a debit to account receivable (client account) and a credit to sales account. which is as shown below:

<em>Dr   Account Receivable $2,250</em>

<em>Cr   Sales  $2,250</em>

<em>Being sales on credit to a client.</em>

The client account will have an outstanding debit balance of <em>$2,250 </em>until payment is made. once payment is made, the following entries will be made to ensure no outstanding balance in the client account.

Dr   Cash/Bank $2,250

Cr   Account Receivable $2,250.

7 0
3 years ago
Calculator
Sedaia [141]

Check the picture below.

so let's find the lengths of those two sides in red, since are the length and width of the rectangle.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-3}~,~\stackrel{y_2}{6})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{[-3-(-6)]^2+[6-3]^2}\implies d=\sqrt{(-3+6)^2+(6-3)^2} \\\\\\ d=\sqrt{9+9}\implies \boxed{d=\sqrt{18}} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-1})~\hfill d=\sqrt{[-2-(-6)]^2+[-1-3]^2} \\\\\\ d=\sqrt{(-2+6)^2+(-1-3)^2}\implies d=\sqrt{16+16}\implies \boxed{d=\sqrt{32}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of the rectangle}}{(\sqrt{18})(\sqrt{32})}\implies \sqrt{18\cdot 32}\implies \sqrt{576}\implies 24

7 0
3 years ago
Name two intersecting line segments that are not perpendicular.
liubo4ka [24]
I don't see anything, but any line that doensnt have the right angle sign is not perpendicular. 
4 0
3 years ago
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