A customer borrowed $2000 and then a further $1000 both repayble in 12 months. What would he have saved if he had taken out one loan for $3000 repayable in 12 months?
He took two different loans, it charged him loan processing fee twice, two-time documentation process, and of course, extra time spent for second loan. Instead, he could take single loan of $3000 with one-time processing fee, one-time documentation process, and time-saving also.
$15 is the original purchase. $12 and hour.
15+12y
The locomotive is 40 ft long.
40 ft = 40 * 12 in. = 480 in.
The locomotive is 480 inches line.
The model is 16 inches long.
480/16 = 30
The real locomotive is 30 times longer than the model.
A window on the locomotive is 30 times wider than a window on the model.
3(x^2+10x+5)-5(x-k)=
3x^2+30x+15-5x+5k=
3x^2+25x+15+5k
for this to be divisible by x every term must include x or get eliminated
the problematic terms are 15 and 5k
to eliminate them they must equal 0 when added:
15+5k=0
5k=-15
k=-3
so A) -3 is the solution
Answer:
The correct answer is C.
2x² + 7x - 30 is equal to (2x−5)(x+6)
Step-by-step explanation:
2x² + 7x - 30
= 2x² − 5x + 12x − 30
= (2x−5)(x+6)
