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sp2606 [1]
3 years ago
11

Help Please!! Ill Give Brainliest!

Mathematics
2 answers:
Anestetic [448]3 years ago
5 0

this question is over and over the same thing

vladimir1956 [14]3 years ago
3 0

Question:

On a coordinate grid, point A is located in the first quadrant. Point B is located at (negative 1 over 2, 2).

Point C is a reflection of point B across the y-axis. Which graph shows these three points?

Answer:

What are you telling me? I would help, but can you type in answer choices if there is. That would be very helpful. I don't understand what is " A coordinate grid from negative 3 to positive 3 on both axes is drawn in increments of 1 over 2. Point A is plotted 4 grid lines to the right of the y-axis and 1 grid line above the axis. Point B is plotted at 1 grid line to the left of the y-axis and 4 grid lines above the x-axis. Point C is plotted at 1 grid line to the left of the y-axis and 4 grid lines below the x-axis.

A coordinate grid from negative 3 to positive 3 on both axes is drawn in increments of 1 over 2. Point A is plotted 4 grid lines to the right of the y-axis and 1 grid line above the x-axis. Point B is plotted at 1 grid line to the left of the y-axis and 4 grid lines above the x-axis. Point C is plotted at 1 grid line to the right of the y-axis and 4 grid lines above the x-axis.

A coordinate grid from negative 3 to positive 3 on both axes is drawn in increments of 1 over 2. Point A is plotted 2 grid lines to the left of the y-axis and 4 grid lines above the axis. Point B is plotted at 1 grid line to the right of the y-axis and 4 grid lines above the x-axis. Point C is plotted at 1 grid line to the left of the y-axis and 4 grid lines below the x-axis.

A coordinate grid from negative 3 to positive 3 on both axes is drawn in increments of 1 over 2. Point A is plotted 2 grid lines to the left of the y-axis and 4 grid lines above the axis. Point B is plotted at 1 grid line to the right of the y-axis and 4 grid lines above the x-axis. Point C is plotted at 1 grid line to the right of the y-axis and 4 grid lines below the x-axis."

Step-by-step explanation:

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The roots of 2x^2-3x=4 are a and b. Find the simplest quadratic equation which has roots 1/a and 1/b
Tju [1.3M]
Find the roots

solve
we use hmm, completing the suare
2(x²-1.5x)=4
divide both sides by 2
x²-1.5x=2
take 1/2 of linear coeiftn and square it
-1.5/2=-0.75, (-0.75)²=0.5625
add that to both sides
x²-1.5x+0.5625=2+0.5625
factor perfect squaer trinomial
(x-0.75)²=2.5625
square root both sides, remember to take positive and negative square roots
x-0.75=+/-√2.5625
add 0.75 to both sides
x=0.75+/-√2.5625

the roots are x=0.75+√2.5625 and x=0.75-√2.5625

1/a and 1/b
1/(0.75+√2.5625) and 1/(0.75-√2.5625)

if the roots of a quadratic equation are r1 and r2 then it factors to
(x-r1)(x-r2)
so then we can factor our equation to be
(x-\frac{1}{0.75+\sqrt{2.5625}})(x-\frac{1}{0.75-\sqrt{2.5625}})

if we were to try and expand it, we would get
x²+0.75x-0.5
that's the simpliest equation with roots 1/a and 1/b where a and b are he roots of 2x²-3x=4


x²+0.75x-0.5 is answer
8 0
3 years ago
Ben has a cell phone plan that provides 200 free minutes each month for a flat rate of $39. For any minutes over 200, Ben is cha
faltersainse [42]

Answer:

\left\{\begin{matrix}39 & x\leq 200\\ 39+(x-200)\times 0.35 & x>200\end{matrix}\right.

Step-by-step explanation:

We are given that Ben has a cell phone plan that provides 200 free minutes each month for a flat rate of $39.

We are also told that For any minutes over 200, Ben is charged $0.35 per minute.

let x  be the minutes used each month

So, if x\leq 200

So, coat will be $39

If x>200

So, Ben is charged $0.35 per minute

So, when x>200

So, charge = 39+(x-200)\times 0.35

So, the piecewise functions accurately represents charges based on Ben's cell phone :

\left\{\begin{matrix}39 & x\leq 200\\ 39+(x-200)\times 0.35 & x>200\end{matrix}\right.

4 0
3 years ago
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R=7

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Where is the figure????

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i think the answer is A.

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