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pantera1 [17]
3 years ago
14

9.

Mathematics
1 answer:
Mashcka [7]3 years ago
4 0
To solve this we are going to use the formula for compounded interest: A=P(1+ \frac{r}{n})^{nt}
where 
A is the final amount after t years 
P is the initial amount 
r is the interest rate in decimal form 
n is the number of times the interest is compounded per year
t is the time in years 

We know for our problem that P=1380, r= \frac{5}{100} =0.05, and t=3. Since the interest is compounded daily, it is compounded 365 times in year; therefore, n=365. Lets replace those values in our formula to find A:
A=P(1+ \frac{r}{n})^{nt}
A=1380(1+ \frac{0.05}{365})^{(365)(3)}
A=1603.31

We can conclude the amount in Diane's after 3 years will be <span>$1,603.31</span>
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Answer:

Following are the answer to this question:

Step-by-step explanation:

Given:

n = 30 is the sample size.  

The mean  \bar X = 7.3 days.  

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The table value is calculated with a function excel 2010:

= tinv (\ probility, \ freedom \ level) \\= tinv (0.10,29) \\ =1.699127\\ =  t_{al(2x-1)}= 1.699127

The method for calculating the trust interval of 90 percent for the true population means is:

Formula:

\bar X - t_{al 2,x-1} \frac{S}{\sqrt{n}} \leq \mu \leq \bar X+ t_{al 2,x-1}   \frac{S}{\sqrt{n}}

=\bar X - t_{0.5, 29} \frac{6.2}{\sqrt{30}} \leq \mu \leq \bar X+ t_{0.5, 29}   \frac{6.2}{\sqrt{30}}\\\\=7.3 -1.699127 \frac{6.2}{\sqrt{30}}\leq \mu \leq7.3 +1.699127 \frac{6.2}{\sqrt{30}}\\\\=7.3 -1.699127 (1.13196)\leq \mu \leq7.3 +1.699127  (1.13196) \\\\=5.37 \leq \mu  \leq 9.22 \\

It can rest assured that the true people needs that middle managers are unavailable from 5,37 to 9,23 during the years.

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