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miskamm [114]
3 years ago
12

If you buy 5 bags of popcorn and each bag cost $7 would it be 35? by multipling?;)

Mathematics
2 answers:
Brrunno [24]3 years ago
8 0

Yes, 35$ is indeed the correct answer.

Multiplication is repeated addition so if you haven't memorized the times table, you can work through this by adding 7 to itself for a total of 5 times: 7 + 7 + 7 + 7 + 7 = 35

ASHA 777 [7]3 years ago
4 0
Yes, 5*7=35
++++++++++++
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Convert each measure into radians
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Answer: -240 = -4π / 3, 60 = π / 3, 270 = 3π / 2, 945 = 21π / 4, -30 = -π / 60, 195 = 13π / 12

Step-by-step explanation:

The formula for converting <em>Degrees </em>into <em>Radians </em>is <em>Degrees </em>* (π / 180) = <em>Radians</em>.

For -240, we have -240 * (π / 180) = -240π / 180 and simplifying gives us -4π / 3

60:  60 * (π / 180) = 60π / 180 = π/3

270:  270 * (π / 180) = 270π / 180 = 3π / 2

945:  945 * (π / 180) = 945π / 180 = 21π / 4

-30:  -30 * (π / 180) = -30π / 180 = π / 60

195:  195 * (π / 180) = 195π / 180 = 13π / 12

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2 years ago
1. The original price of the table was $250. Jane bought it on sale for $200.
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She saved 50$ but saved 20%
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2 years ago
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Piper is helping her dad lay out purple tiles to make completed they have done all of this they are 16 tiles and they filled it
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Answer:

9 tiles needed to fill

Step-by-step explanation:

16 - 7

6 0
3 years ago
A zoologist is studying four very closely related feline species. She wishes to compare their gestation periods. An observationa
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Answer:

p_v= 0.01

Since the significance level is 0.05 we see that pv so we have enough evidence to reject the null hypothesis. And the best conclusion for this case would be:

b. at least some, but not all, of the gestation periods across all four species are the same

Because is only to identify if AT LEAST one mean is different, NOT to conclude that the all the means are different.

Step-by-step explanation:

Previous concepts

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".  

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"  

Solution to the problem

The hypothesis for this case are:

Null hypothesis: \mu_{A}=\mu_{B}=\mu_{C}= \mu_D

Alternative hypothesis: Not all the means are equal \mu_{i}\neq \mu_{j}, i,j=A,B,C,D

In order to find the mean square between treatments (MSTR), we need to find first the sum of squares and the degrees of freedom.

If we assume that we have p=4 groups and on each group from j=1,\dots,p we have n_j individuals on each group we can define the following formulas of variation:  

SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2  

SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2  

SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2  

And we have this property  

SST=SS_{between}+SS_{within}  

And in order to test this hypothesis we need to ue an F statistic and for this case the p value calculated is

p_v= 0.01

Since the significance level is 0.05 we see that pv so we have enough evidence to reject the null hypothesis. And the best conclusion for this case would be:

b. at least some, but not all, of the gestation periods across all four species are the same

Because is only to identify if AT LEAST one mean is different NOT to conclude that the all the means are different.

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3 years ago
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Since 1 ton is 2,000 lbs, each Crib Jack can life 30,000 lbs. It's going to take 2 Crib Jacks, because the extra 5,000 lbs in belongings were removed, leaving the house at a weight of 60,000 lbs. 
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