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svp [43]
3 years ago
15

2m-13=8m+27-71 how do you do this

Mathematics
2 answers:
ivolga24 [154]3 years ago
8 0

I just reorder it and range it

Shtirlitz [24]3 years ago
5 0

Answer:

31/6  (Fraction)

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What is the answer to -8(-1)•1(-4)
horsena [70]

The answer is -32.  This is because when you multiply to negatives it becomes a positive.  So its 8*-4 making the answer be -32.

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3 years ago
A company has two large computers. The slower computer can send all the company's email in 45 minutes. The faster computer can c
tatuchka [14]

Answer

It would take them the same amount of time as it normally took.

Which would be 30 and 45 minutes.

please feel free to ask me some more questions, or clarify.

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3 years ago
Which of these side lengths makes the triangle obtuse?<br> 15, 36,
gogolik [260]

Answer:

I believe the answer is 36.

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3 years ago
The radius of a cone is increasing at a constant rate of 7 meters per minute, and the volume is decreasing at a rate of 236 cubi
storchak [24]

Answer:

The rate of change of the height is 0.021 meters per minute

Step-by-step explanation:

From the formula

V = \frac{1}{3}\pi r^{2}h

Differentiate the equation with respect to time t, such that

\frac{d}{dt} (V) = \frac{d}{dt} (\frac{1}{3}\pi r^{2}h)

\frac{dV}{dt} = \frac{1}{3}\pi \frac{d}{dt} (r^{2}h)

To differentiate the product,

Let r² = u, so that

\frac{dV}{dt} = \frac{1}{3}\pi \frac{d}{dt} (uh)

Then, using product rule

\frac{dV}{dt} = \frac{1}{3}\pi [u\frac{dh}{dt} + h\frac{du}{dt}]

Since u = r^{2}

Then, \frac{du}{dr} = 2r

Using the Chain's rule

\frac{du}{dt} = \frac{du}{dr} \times \frac{dr}{dt}

∴ \frac{dV}{dt} = \frac{1}{3}\pi [u\frac{dh}{dt} + h(\frac{du}{dr} \times \frac{dr}{dt})]

Then,

\frac{dV}{dt} = \frac{1}{3}\pi [r^{2} \frac{dh}{dt} + h(2r) \frac{dr}{dt}]

Now,

From the question

\frac{dr}{dt} = 7 m/min

\frac{dV}{dt} = 236 m^{3}/min

At the instant when r = 99 m

and V = 180 m^{3}

We will determine the value of h, using

V = \frac{1}{3}\pi r^{2}h

180 = \frac{1}{3}\pi (99)^{2}h

180 \times 3 = 9801\pi h

h =\frac{540}{9801\pi }

h =\frac{20}{363\pi }

Now, Putting the parameters into the equation

\frac{dV}{dt} = \frac{1}{3}\pi [r^{2} \frac{dh}{dt} + h(2r) \frac{dr}{dt}]

236 = \frac{1}{3}\pi [(99)^{2} \frac{dh}{dt} + (\frac{20}{363\pi }) (2(99)) (7)]

236 \times 3 = \pi [9801 \frac{dh}{dt} + (\frac{20}{363\pi }) 1386]

708 = 9801\pi \frac{dh}{dt} + \frac{27720}{363}

708 = 30790.75 \frac{dh}{dt} + 76.36

708 - 76.36 = 30790.75\frac{dh}{dt}

631.64 = 30790.75\frac{dh}{dt}

\frac{dh}{dt}= \frac{631.64}{30790.75}

\frac{dh}{dt} = 0.021 m/min

Hence, the rate of change of the height is 0.021 meters per minute.

3 0
3 years ago
Use the Order of Operations to simplify: 3(8 - 4*5)
aleksklad [387]

Answer:

<h2>-36</h2>

Step-by-step explanation:

3\left(8-4\cdot \:5\right)\\\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}\\\\\mathrm{Calculate\:within\:parentheses}\:\left(8-4\cdot \:5\right)\::\quad -12\\=3\left(-12\right)\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:3\left(-12\right)\:\\:\quad -36

3 0
3 years ago
Read 2 more answers
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