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3 years ago

WOULD THIS BE RIGHTTT PLEASE NO BS

Mathematics

1 answer:

coldgirl [10]3 years ago

3 0

Answer:

no its not right

the line doesn't pass by (2,0) it passes by (2,1)

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Can i get a list of prime numbers

bija089 [108]

well prime numbers are noting but whole number greater than 1 whose only factors are 1 and itself.

soo....the first few prime numbers are :

2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149 etc.

and if u c .... all the numbers dont come in any other table rather that one and itself

5 0

3 years ago

How do I solve this? And what's the answer.. I'm so lost.

Naya [18.7K]

The square root of 100= 10 because 10^2 or 10*10= 100

The cube root of 64 is 4 because 4^3 or 4*4*4= 64

10-4=6

Final answer: C

5 0

3 years ago

Find the smallest square number that is divisible by each of the numbers 8, 9 and 10

vekshin1

Answer:

Step-by-step explanation:

Find the LCM of 8,9 and 10.

Prime Factorization to find LCM,

8 = 2 × 2 × 2

9 = 3 × 3

10 = 2 × 5

LCM ( 8 , 9 , 10 ) = 2 × 2 × 2 × 3 × 3 × 5 =360

But 360 is not square

Now we make the pairs complete by multiplying same numbers in prime factorization of LCM.

We need one 2 and one 5 to complete the pair.

We get, Least Square number = 2 × 2 × 2 × 2 × 3 × 3 × 5 × 5 = 3600

Hope this helps

good Luck

7 0

4 years ago

Read 2 more answers

Factor using the identity: a3 + b3 = (a + b)(a2 – ab + b2) 8z3 + 27

vivado [14]

Answer: this is our required factor i.e.

$8z^3+27=(2z+3)(4z^2-6z+9)$

Explanation:

Since we have given that

$8z^3+27$

As we know the identity , which says that

$a^3+b^3=(a+b)(a^2-ab+b^2)$

So, we can use this here ,

$8z^3+27=(2z)^3+3^3\\\\=(2z+3)((2z)^2-2z\times 3+3^2)\\\\=(2z+3)(4z^2-6z+9)$

Hence this is our required factor i.e.

$8z^3+27=(2z+3)(4z^2-6z+9)$

7 0

3 years ago

Read 2 more answers

A physics student stands at the top of a hill that has an elevation of 56 meters. he throws a rock and it goes up into the air a

horrorfan [7]

find a starting point on the top distance in meters the answer is B

8 0

4 years ago