The domain of the function is the range of values of x that can be used to be replaced in the equation for it to become true. We are given that the value of f(x) should range only from -1 to 3. We evaluate each of the choices and see if the values of f(x) will fall within the range.
(a) -12; f(x) = 2^(-12) - 10 = -9.9999 (NOT AN ANSWER)
(b) -10; f(x) = 2^(-10) - 10 = -9.999 (NOT AN ANSWER)
(c) -9; f(x) = 2^(-9) - 10 = -9.999 (NOT AN ANSWER)
(d) -6; f(x) = 2^(-6) - 10 = -9.98 (NOT AN ANSWER)
(e) -2; f(x) = 2^(-2) - 10 = -9.75 (NOT AN ANSWER)
Hence, none of the choices will allow the value of f(x) to fall between -1 and 3.
Do you need an equation?
y=2x+10
2x represents each hour, 10 represents renting fee
Answer:
Answer 5 1/4
Step-by-step explanation:
Answer:
x = 2.81 and 2.096
Step-by-step explanation:
Given the expression
10(2^x) + 7(3^x) = 6^x + 70
This can also be expressed as;
10(2^x) + 7(3^x) = (2*3)^x + 70
10(2^x) + 7(3^x) = 2^x*3^x + 70
Let a = 2^x and b = 3^x
10a + 7b = ab + 70
10a + 7b - ab = 70
10a-ab + 7b - 70 = 0
a(10-b)+7(b-10) = 0
a(10-b)-7(10-b) = 0
a-7 = 0 and 10-b = 0
a = 7 and b = 10
Since a = 2^x
7 = 2^x
log 7 = log2^x
log7 = xlog2
x = log7/log2
x = 2.81
Similarly
10 = 3^x
log 10 = log 3^x
log 10 = xlog3
x = log 10/log 3
x = 1/0.4771
x = 2.096
Hence the values of x that satisfies the equation are 2.81 and 2.096
<h3>
Answer: 79 full rotations</h3>
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Explanation:
150 cm = 150/100 = 1.5 m
The wheel has a diameter of 1.5 meters
The circumference of the wheel is
C = pi*d
C = pi*1.5
C = 1.5pi
C = 4.71238898038469
I'm using my calculator's stored version of pi to get the most accuracy.
Then we divide the 376.8 over the circumference found
(376.8)/(4.71238898038469) = 79.9594434093682
Despite being very close to 80, we must round down to 79 because we don't have enough to get that full 80th rotation. In other words, we have 79 full rotations and then some change leftover.
Though for the sake of simplicity, I can see how it's useful to say "about 80 rotations" if 79 seems a bit clunky. I'll stick with 79 however. Let me know if your teacher instructs otherwise.
