Answer: The correct option is
(A) (11, 3).
Step-by-step explanation: We are given to find the co-ordinates of he point that is one-sixth of the way from A(14, −1) to B(−4, 23).
As shown in the attached figure below, let point P is one-sixth of the way from A to B.
Also, let P divides the the segment AB in the ratio m : n.
Then, we must have

So, the point P divides AB in the ratio 1 : 5.
We know that
if a point divides the line segment joining the points (a, b) and (c, d) in the ratio m : n, then its co-ordinates are

Therefore, the co-ordinates of the point P will be

Thus, the required co-ordinates of the point is (11, 3).
Option (A) is CORRECT.