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3 years ago

-3y+5x=26,-2y-5x=-16

Mathematics

2 answers:

ch4aika [34]3 years ago

6 0

Answer:

x=4

y=-2

Step-by-step explanation:

We are give two linear equations and asked to solve them. The two equations are

-3y+5x=26

-2y-5x=-16

Adding both equations

-5y=10

Dividing both sides by -5

y=-2

Substitute y=-2 in first equation

-3(-2)+5x=26

6+5x=26

5x=20

Dividing both sides by 5

x=4

Nataliya [291]3 years ago

3 0

Answer:

x = 4 , y = − 2

Step-by-step explanation:

Add the equations in order to solve for the first variable. Plug this value into the other equations in order to solve for the remaining variables.

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3 years ago

The computer that controls a bank's automatic teller machine crashes a mean of 0.6 times per day. What is the probability that,

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Answer:

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

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7 day week, so $\mu = 7*0.6 = 4.2$

What is the probability that, in any seven-day week, the computer will crash less than 3 times? Round your answer to four decimal places.

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-4.2}*(4.2)^{0}}{(0)!} = 0.0150$

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$P(X = 2) = \frac{e^{-4.2}*(4.2)^{2}}{(2)!} = 0.1323$

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0150 + 0.0630 + 0.1323 = 0.2103$

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

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