<span>mRNA: UACAUGGCCUUACGCUAA
tRNA: AUG UAC CGG AAU GCG AUU
a.a: Tyrosine, Methionine, Alanine, Leucine, and Arginine
DNA has 4 different bases, they are Adenine (A), cytosine (C), guanine (G), and Thymine (T). RNA also has 4 bases with three of them being identical to the DNA bases and Thymine being replaced with Uracil (U). These bases are generally represented by the 1st letter of their names. Each of the bases will join with a complementary base, so A always pairs with T or U, and C will pair with G. So to create the mRNA, simply replace every A with a U, every C with a G, every G with a C, and finally, every T with a A. So
mRNA: UACAUGGCCUUACGCUAA
Now for tRNA, there's a slight twist. It only comes in 3 base codons, You won't find a sequence of tRNA other than in 3 base codons. And each of those codons will be uniquely paired with an amino acid. In the ribosomes, the mRNA will be sequentially scanned 3 bases at a time allowing for a matching tRNA sequence to bind to the exposed 3 bases, this will cause the next amino acid to be bound into the protein being constructed. So split the mRNA into 3 base sequences and calculate the complement to get the tRNA. A simple shortcut is to look at the original DNA sequence and simply replace a T bases with U. So
tRNA: AUG UAC CGG AAU GCG AUU
Notice the spaces every 3rd base. THIS IS REQUIRED. These is no continuous length of tRNA. You'll only find it in 3 base lengths and each of them will be bound with an amino acid.
For the amino acid that's coded to the RNA, you'll need to use a lookup table in your text book, or one you can find online. Then it's a simple matter of matching each 3 base sequence to the amino acid. For the sequence given we have:
AUG - Tyrosine
UAC - Methionine
CGG - Alanine
AAU - Leucine
GCG - Arginine
AUU - STOP
Notice the AUU doesn't decode to a specific amino acid. It instead indicates to the ribosome to stop the production of the protein. So the amino acid sequence for the originally given DNA sequence is:
Tyrosine, Methionine, Alanine, Leucine, and Arginine.</span>
<h2>Answer</h2>
A single celled salt water protozoan is transferred to a a freshwater lake. What might happen to the protozoan
- it would gain water from the hypertonic solution. It it can't get rid of the pressure, it will burst.
<h3>#CarryOnLearning</h3>
D.
Selective breeding
In selective breeding, the desired genes from one organism are combined with genes of another organism, resulting in a new combination of genes.
<span>The selective breeding is quite voluntary and is not necessarily natural or congenital. It is the act of how people or individuals can choose traits in the gene pool of their choice to produce their desired or goal organism in the process. This trait is influenced in the host of the specific sperm and egg cell which makes up the chromosomes. </span>
Answer:
"As a molecule moves through the plasma membrane it passes through <em>a hydrophilic layer of phospholipid heads then a hydrophobic layer of phospholipid tails and then another hydrophilic layer of phospholipid heads".</em>
Explanation:
Biological membranes are formed by two lipidic layers, proteins, and glucans.
Lipids characterize for being amphipathic molecules, which means that they have both a hydrophilic portion and a hydrophobic portion at the same time. These molecules have a lipidic head that corresponds to a negatively charged phosphate group, which is the polar and hydrophilic portion. They also have two lipidic tails that correspond to the hydrocarbon chains -the apolar and hydrophobic portion- of the fatty acids that esterify glycerol.
Membrane lipids are arranged with their hydrophilic polar heads facing the exterior and the interior of the cells, while their hydrophobic tails are against each other, constituting the internal part of the membrane.
Through this lipidic bilayer, some molecules can move from one side of the cell to the other, which happens because of concentration differences. When this occurs, molecules must pass through the hydrophilic layer of phospholipid heads then through the hydrophobic layer of phospholipid tails and then again through another hydrophilic layer of phospholipid heads.
This is because it is a monocot and monocots do not have a vascular cambium in their stems.
