Answer:
m<FED=60, m<DEN=120
Step-by-step explanation:
m<FED=60
This is because <GEN and <FED are vertical angles.
Vertical angles are always congruent.
Vertical angles are formed by a pair of intersecting lines, and are the angles directly across from one another.
m<DEN=120
This is because <DEN and <GEN are supplementary.
Supplementary angles add up to 180 degrees.
We know this because a straight line is always 180 degrees.
So:
m<DEN+m<GEN=180
m<DEN+60=180
m<DEN=120
You subtract 16 from each side of the equation.
Then it will say exactly what number 'n' is.
_______________________________________
The equation is n + 16 = 9
On the left side, you subtract 16 from (n + 16) and you have 'n'.
On the right side, you subtract 16 from 9 and you have -7 .
Now the equation says n = -7
Answer:
go where they do school on
Step-by-step explanation:
Given:
h = high quality bean ; costs 6 per pound
c = cheaper bean ; costs 3.25 per pound
160 pounds of blended coffee beans at 4.97 per pound
h + c = 160
6h + 3.25c = 160(4.97)
6h + 3.25c = 795.20
h = 160 - c
6(160-c) + 3.25c = 795.20
960 - 6c + 3.25c = 795.20
- 2.75c = 795.20 - 960
- 2.75c = -164.80
c = - 164.80 / -2.75
c = 59.92 or 60 pounds
h = 160 - c
h = 160 - 60
h = 100 pounds
Sarah must blend 100 pounds of high quality bean and 60 pounds of cheaper bean.
Answer:
![Probability = 0.504](https://tex.z-dn.net/?f=Probability%20%3D%200.504)
Step-by-step explanation:
Given
![Gems= 35](https://tex.z-dn.net/?f=Gems%3D%2035)
![Real = 10](https://tex.z-dn.net/?f=Real%20%3D%2010)
![Fake = 25](https://tex.z-dn.net/?f=Fake%20%3D%2025)
Required
Determine the probability of selecting two fakes
The probability can be represented as thus: ![P(Fake\ and\ Fake)](https://tex.z-dn.net/?f=P%28Fake%5C%20and%5C%20Fake%29)
Using the following probability formula, we have:
![P(Fake\ and\ Fake) = P(Fake) * P(Fake)](https://tex.z-dn.net/?f=P%28Fake%5C%20and%5C%20Fake%29%20%3D%20P%28Fake%29%20%2A%20P%28Fake%29)
Each probability is calculated by dividing number of fakes by total number of gems:
![P(Fake\ and\ Fake) = \frac{25}{35} * \frac{25-1}{35-1}](https://tex.z-dn.net/?f=P%28Fake%5C%20and%5C%20Fake%29%20%3D%20%5Cfrac%7B25%7D%7B35%7D%20%2A%20%5Cfrac%7B25-1%7D%7B35-1%7D)
The minus 1 (-1) represent the numbers of fake and total gems left after the first selection
![P(Fake\ and\ Fake) = \frac{25}{35} * \frac{24}{34}](https://tex.z-dn.net/?f=P%28Fake%5C%20and%5C%20Fake%29%20%3D%20%5Cfrac%7B25%7D%7B35%7D%20%2A%20%5Cfrac%7B24%7D%7B34%7D)
![P(Fake\ and\ Fake) = \frac{5}{7} * \frac{12}{17}](https://tex.z-dn.net/?f=P%28Fake%5C%20and%5C%20Fake%29%20%3D%20%5Cfrac%7B5%7D%7B7%7D%20%2A%20%5Cfrac%7B12%7D%7B17%7D)
![P(Fake\ and\ Fake) = \frac{60}{119}](https://tex.z-dn.net/?f=P%28Fake%5C%20and%5C%20Fake%29%20%3D%20%5Cfrac%7B60%7D%7B119%7D)
![P(Fake\ and\ Fake) = 0.504](https://tex.z-dn.net/?f=P%28Fake%5C%20and%5C%20Fake%29%20%3D%200.504)
<em>Hence, the required probability is approximately 0.504</em>